cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A332077 Square array of sunflower numbers Sun(m,n) = minimal number of distinct sets of cardinality <= m such that there is a sunflower with at least n sets among them, read by falling antidiagonals; m, n >= 1.

Original entry on oeis.org

1, 2, 1, 3, 2, 1, 4, 7, 2, 1, 5, 11, 21, 2, 1, 6, 21
Offset: 1

Views

Author

M. F. Hasler, Jul 27 2020

Keywords

Comments

A sunflower S is a collection of sets such that all pairwise intersections of distinct A, B in S are equal. The intersection of all the sets is called the core or kernel of S.
Some authors (e.g., Wikipedia) use "more than" instead of "at least" in the definition, which corresponds to an index n decreased by 1. We use the same conventions Tao (but following OEIS standards we use m,n instead of k,r). Also, some authors (e.g., Abbott et al. and the Polymath wiki page) use f(k,r) = Sun(k,r) - 1 which is not the minimal number of required sets, but such that any collection of *more than* f(k,r) sets has the given property.
Bell et al. improve Rao's bound [as reproved by Tao] from Sun(m,n) <= O(n log(mn))^m for m, n >= 2 to the slightly cleaner bound Sun(m,n) <= O(n log m)^m for m, n >= 2. [Pers. comm. from L. Warnke.] - M. F. Hasler, May 02 2021

Examples

			The table starts:
   m \n=1   2   3   4   5   6   7  ...
  ---+-------------------------------
   1 |  1   2   3   4   5   6   7  ...
   2 |  1   2   7  11  21  28  43  ...
   3 |  1   2  21  ...
   4 |  1   2  ...
   5 |  1   2  ...
    ...
Row m=1 has Sun(1,n) = n for all n, because any collection of n sets having at most 1 element (which may or may not include the empty set) makes up an n-petal sunflower S with an empty kernel.
Columns n=1 and n=2 have Sun(m,n) = n for any m, because any single set A makes up a 1-petal sunflower S = {A}, and any two distinct sets A, B make up a 2-petal sunflower S = {A, B} with kernel {A intersect B}, necessarily not equal to both A and B since they are distinct; then so the petals with at least one of them nonempty.
		

Crossrefs

Formula

Sun(m,n) = n for n <= 2 and all m;
Sun(1,n) = n for all n: see Examples for explanation.
Sun(2,n) = n(n-1)+1 if n is odd, (n-1)^2-n/2 if n is even. (Abbott-Hanson-Sauer)
(n-1)^m <= Sun(m,n) <= (n-1)^m*m! + 1. (Erdös & Rado)
Sun(m,n) <= O(n log(mn))^m for m, n >= 2. (Rao)
Sun(m,n) <= O(n log m)^m for m, n >= 2. (Bell-Chueluecha-Warnke)
Sunflower conjecture: Sun(m,n) <= (n*O(1))^m.

A335322 Triangle read by rows: T(n, k) = binomial(n, floor((n+k+1)/2)) with k <= n.

Original entry on oeis.org

1, 1, 1, 3, 1, 1, 4, 4, 1, 1, 10, 5, 5, 1, 1, 15, 15, 6, 6, 1, 1, 35, 21, 21, 7, 7, 1, 1, 56, 56, 28, 28, 8, 8, 1, 1, 126, 84, 84, 36, 36, 9, 9, 1, 1, 210, 210, 120, 120, 45, 45, 10, 10, 1, 1, 462, 330, 330, 165, 165, 55, 55, 11, 11, 1, 1, 792, 792, 495, 495, 220, 220, 66, 66, 12, 12, 1, 1
Offset: 1

Views

Author

Stefano Spezia, May 31 2020

Keywords

Comments

T(n, k) is a tight upper bound of the cardinality of an intersecting Sperner family or antichain of the set {1, 2,..., n}, where every collection of pairwise independent subsets is characterized by an intersection of cardinality at least k (see Theorem 1.3 in Wong and Tay).
Equals A061554 with the first row of the array (resp. the first column of the triangle) removed. - Georg Fischer, Jul 26 2023

Examples

			The triangle T(n, k) begins
n\k|  1   2   3   4   5   6   7   8
---+-------------------------------
1  |  1
2  |  1   1
3  |  3   1   1
4  |  4   4   1   1
5  | 10   5   5   1   1
6  | 15  15   6   6   1   1
7  | 35  21  21   7   7   1   1
8  | 56  56  28  28   8   8   1   1
...
		

Crossrefs

Cf. A037951 (k=3), A037952 (k=1), A037953 (k=5), A037954 (k=7), A037955 (k=2), A037956 (k=4), A037957 (k=6), A037958 (k=8), A045621 (row sums).

Programs

  • Mathematica
    T[n_,k_]:=Binomial[n,Floor[(n+k+1)/2]]; Table[T[n,k],{n,12},{k,n}]//Flatten
  • PARI
    T(n, k) = binomial(n, (n+k+1)\2);
    vector(10, n, vector(n, k, T(n, k))) \\ Michel Marcus, Jun 01 2020

Formula

T(n, k) = A007318(n, A004526(n+k+1)) with k <= n.
Showing 1-2 of 2 results.