A269419 a(n) is denominator of y(n), where y(n+1) = (25*n^2-1)/48 * y(n) + (1/2)*Sum_{k=1..n}y(k)*y(n+1-k), with y(0) = -1.
1, 48, 4608, 55296, 42467328, 84934656, 21743271936, 36691771392, 400771988324352, 1352605460594688, 16620815899787526144, 779100745302540288, 153177439332441840943104, 2393397489569403764736, 235280546814630667688607744, 57441539749665690353664
Offset: 0
Examples
For n=0 we have t(0) = (-1) / (2^(-2)*gamma(-1/2)) = 2/sqrt(Pi). For n=1 we have t(1) = (1/48) / (2^(-1)*gamma(2)) = 1/24. n y(n) t(n) 0 -1 2/sqrt(Pi) 1 1/48 1/24 2 49/4608 7/(4320*sqrt(Pi)) 3 1225/55296 245/15925248 4 4412401/42467328 37079/(96074035200*sqrt(Pi)) 5 73560025/84934656 38213/14089640214528 6 245229441961/21743271936 5004682489/(92499927372103680000*sqrt(Pi)) 7 7759635184525/36691771392 6334396069/20054053184087387013120 ...
Links
- Gheorghe Coserea, Table of n, a(n) for n = 0..500
- Edward A. Bender, Zhicheng Gao, L. Bruce Richmond, The map asymptotics constant tg, The Electronic Journal of Combinatorics, Volume 15 (2008), Research Paper #R51.
- Stavros Garoufalidis, Thang T.Q. Le, Marcos Marino, Analyticity of the Free Energy of a Closed 3-Manifold, arXiv:0809.2572 [math.GT], 2008.
Programs
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Mathematica
y[0] = -1; y[n_] := y[n] = (25(n-1)^2-1)/48 y[n-1] + 1/2 Sum[y[k] y[n-k], {k, 1, n-1}]; Table[y[n] // Denominator, {n, 0, 15}] (* Jean-François Alcover, Oct 23 2018 *)
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PARI
seq(n) = { my(y = vector(n)); y[1] = 1/48; for (g = 1, n-1, y[g+1] = (25*g^2-1)/48 * y[g] + 1/2*sum(k = 1, g, y[k]*y[g+1-k])); return(concat(-1,y)); } apply(denominator, seq(14))