cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A272036 Numbers n such that the sum of the inverse of the exponents in the binary expansion of 2n is equal to 1.

Original entry on oeis.org

1, 38, 2090, 16902, 18954, 18988, 131334, 133386, 133420, 148258, 150284, 524314, 524348, 526386, 541212, 543250, 543284, 655644, 657682, 657716, 672568, 674580, 8388742, 8390794, 8390828, 8405666, 8407692, 8520098, 8522124, 8536962, 8536996, 8539048, 8913052, 8915090
Offset: 1

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Author

Michel Marcus, Apr 18 2016

Keywords

Comments

That is, numbers such that both A116416(n) and A116417(n) are equal to 1.
Intersection of A272034 and A272035.
A number m with an exponent k in the binary sum must have another power of 2 having an exponent at least A275288(k). - David A. Corneth, Apr 01 2017

Examples

			For n=38, 2*38_10 = 2^6 + 2^3 + 2^2 = 1001100_2, and 1/2 + 1/3 + 1/6 = 1.
		

Crossrefs

Programs

  • Mathematica
    Select[Range[2^20], Total[1/Flatten@ Position[Reverse@ IntegerDigits[#, 2], 1]] == 1 &] (* Michael De Vlieger, Apr 18 2016 *)
  • PARI
    is(n) = my(b = Vecrev(binary(n))); sum(k=1, #b, b[k]/k) == 1;

A272034 Numbers n such that the sum of the inverse of the exponents in the binary expansion of 2n is the inverse of an integer.

Original entry on oeis.org

1, 2, 4, 8, 16, 32, 36, 38, 64, 128, 256, 512, 1024, 2048, 2056, 2080, 2088, 2090, 4096, 8192, 16384, 16896, 16900, 16902, 16928, 18944, 18952, 18954, 18988, 32768, 65536, 131072, 131328, 131332, 131334, 131360, 133376, 133384, 133386, 133420, 148224, 148256, 148258, 150284
Offset: 1

Views

Author

Michel Marcus, Apr 18 2016

Keywords

Comments

That is, numbers such that A116416(n) is equal to 1.
The powers of 2 (A000079) form a subsequence.

Examples

			For n=36, 38_10=100100_2, and 1/3 + 1/6 = 1/2, the inverse of an integer.
		

Crossrefs

Programs

  • Mathematica
    Select[Range[2^18], IntegerQ[1/Total[1/# & /@ Flatten@ Position[Reverse@ IntegerDigits[#, 2], 1]]] &] (* Michael De Vlieger, Apr 18 2016 *)
  • PARI
    isok(n) = {my(b = Vecrev(binary(n))); numerator(sum(k=1, #b, b[k]/k)) == 1;}

A272082 Irregular triangle read by rows: strictly decreasing positive integer sequences in lexicographic order with the property that the sum of inverses is an integer.

Original entry on oeis.org

1, 6, 3, 2, 6, 3, 2, 1, 12, 6, 4, 2, 12, 6, 4, 2, 1, 15, 10, 3, 2, 15, 10, 3, 2, 1, 15, 12, 10, 4, 2, 15, 12, 10, 4, 2, 1, 15, 12, 10, 6, 4, 3, 15, 12, 10, 6, 4, 3, 1, 18, 9, 3, 2, 18, 9, 3, 2, 1, 18, 12, 9, 4, 2, 18, 12, 9, 4, 2, 1, 18, 12, 9, 6, 4, 3, 18, 12
Offset: 1

Views

Author

Peter Kagey, Apr 19 2016

Keywords

Examples

			First 8 rows:
[1]                because 1/1 is an integer
[6, 3, 2]          because 1/6 + 1/3 + 1/2 = 1.
[6, 3, 2, 1]       because 1/6 + 1/3 + 1/2 + 1/1 = 2.
[12, 6, 4, 2]      because 1/12 + 1/6 + 1/4 + 1/2 = 1.
[12, 6, 4, 2, 1]   because 1/12 + 1/6 + 1/4 + 1/2 + 1/1 = 2.
[15, 10, 3, 2]     because 1/15 + 1/10 + 1/3 + 1/2 = 1.
[15, 10, 3, 2, 1]  because 1/15 + 1/10 + 1/3 + 1/2 + 1/1 = 2.
[15, 12, 10, 4, 2] because 1/15 + 1/12 + 1/10 + 1/4 + 1/2 = 1.
		

Crossrefs

Showing 1-3 of 3 results.