A276523 Partition an n X n square into multiple non-congruent integer-sided rectangles. a(n) is the least possible difference between the largest and smallest area.
2, 4, 4, 5, 5, 6, 6, 8, 6, 7, 8, 6, 8, 8, 8, 8, 8, 9, 9, 9, 8, 9, 10, 9, 10, 9, 9, 11, 11, 10, 12, 12, 11, 12, 11, 10, 11, 12, 13, 12, 12, 12, 13, 13, 12, 14, 12, 13, 14, 13, 14, 15, 14, 14, 15, 15, 14, 15, 15, 14, 15, 15, 15
Offset: 3
Examples
A size-11 square can be divided into 3 X 4, 2 X 6, 2 X 7, 3 X 5, 4 X 4, 2 X 8, 2 X 9, and 3 X 6 rectangles. 18 - 12 = 6, the minimal area range. The 14 X 14 square can be divided into non-congruent rectangles of area 30 to 36: aaaaaaaaaabbbb aaaaaaaaaabbbb aaaaaaaaaabbbb cccdddddddbbbb cccdddddddbbbb cccdddddddbbbb cccdddddddbbbb cccdddddddbbbb ccceeeeeffffff ccceeeeeffffff ccceeeeeffffff ccceeeeeffffff ccceeeeeffffff ccceeeeeffffff
Links
- Michel Gaillard, Optimal tilings for n=58..65
- Robert Gerbicz, Optimal tilings for n=3..57
- Gordon Hamilton, Mondrian Art Puzzles (2015).
- Gordon Hamilton and Brady Haran, Mondrian Puzzle, Numberphile video (2016)
- Mersenneforum.org puzzles, Mondrian art puzzles
- Cooper O'Kuhn, The Mondrian Puzzle: A Connection to Number Theory, arXiv:1810.04585 [math.CO], 2018.
- Cooper O'Kuhn and Todd Fellman, The Mondrian Puzzle: A Bound Concerning the M(n)=0 Case, arXiv:2006.12547 [math.NT], 2020. See also Integers (2021) Vol. 21, #A37.
- Ed Pegg Jr, Mondrian Art Problem.
Extensions
Bruce Norskog corrected a(18), and a recheck by Pegg corrected a(15) and a(19). - Charles R Greathouse IV, Nov 28 2016
Correction of a(14), a(16), a(23) and new terms a(25)-a(28) from Robert Gerbicz, Nov 28 2016
a(29)-a(44) from Robert Gerbicz, Dec 02 2016
a(45)-a(47) from Robert Gerbicz added, as well as best known values to a(96).
Correction of a(45), a(46) and new terms a(48)-a(57) from Robert Gerbicz, Dec 27 2016
a(58)-a(65) from Michel Gaillard, Oct 23 2020
Comments