A285110 a(n) = A001222(A285323(n)).
0, 2, 2, 1, 2, 2, 1, 1, 2, 2, 1, 1, 1, 2, 1, 1, 2, 2, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 2, 2, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 2, 2, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 1
Offset: 0
Keywords
Links
- Antti Karttunen, Table of n, a(n) for n = 0..8192
Programs
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Python
from operator import mul from sympy import prime, primefactors from functools import reduce def a001222(n): return 0 if n<2 else a001222(n//min(primefactors(n))) + 1 def a019565(n): return reduce(mul, (prime(i+1) for i, v in enumerate(bin(n)[:1:-1]) if v == '1')) if n > 0 else 1 # This function from Chai Wah Wu def a007947(n): return 1 if n<2 else reduce(mul, primefactors(n)) def a065642(n): if n==1: return 1 r=a007947(n) n += r while a007947(n)!=r: n+=r return n def a285323(n): return a065642(a065642(a019565(n)))//a019565(n) def a(n): return a001222(a285323(n)) print([a(n) for n in range(121)]) # Indranil Ghosh, Apr 20 2017
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Scheme
(define (A285110 n) (A001222 (A285323 n))) (define (A285110 n) (cond ((zero? n) n) ((or (= 1 (A000120 n)) (> (A000040 (+ 1 (A285099 n))) (A000290 (A000040 (+ 1 (A007814 n)))))) 2) (else 1)))
Comments