cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A290821 Side length of largest equilateral triangle that can be made from n or fewer equilateral triangles with integer sides s_k, subject to gcd(s_1,s_2,...,s_n) = 1.

Original entry on oeis.org

1, 1, 1, 2, 2, 3, 4, 5, 7, 9, 12, 16, 21, 28, 39, 49
Offset: 1

Views

Author

Hugo Pfoertner, Aug 11 2017

Keywords

Comments

No construction from 2, 3 or 5 equilateral triangles exists. The first difference from the Padovan numbers occurs for a(15)=39, where the corresponding term A000931(19)=37. a(16)=A000931(20)=49. a(n) >= A000931(n+3). From the growth behavior of A290697 it is conjectured that a(k) > A000931(k+3) for all k > 20.
a(19) is at least 130. This compares with A000931(23) = 114. It hints of growth behavior similar to sqrt(A014529) or sqrt(A001590). Ceiling(sqrt(A001590(n))) matches a(n) to n=14, then runs 38, 52, 70, 95, 128, ... . - Peter Munn, Mar 10 2018
From Peter Munn, Mar 14 2018 re monotonicity: (Start)
For n >= 6, a(n+1) > a(n).
Sketch of proof (inductive step) expressed in terms of tiling:
Given a triangle of side a(n) tiled with n equilateral triangular tiles. Let X, Y and Z be the tiles incident on its vertices, with X being not smaller than Y or Z.
Case 1: Y and Z have no vertices coincident. Remove Y and Z, thereby reducing the tiled area to a pentagon that has edges A and C that were previously internal to the area, and an edge B between A and C. Fit a new tile T against edge B, thereby extending edges A and C. Make the tiled area triangular by fitting a new tile against each of the extended edges.
Case 2: X, Y and Z have pairwise coincident vertices. It follows that these tiles are the same size. Remove Y and Z, thereby reducing the tiled area to a rhombus. Remove the tile at the rhombus vertex opposite X. The remaining area is a pentagon, since n >= 6. Extend the area by resiting Y against X, and Z against Y so that X and Z have external edges aligned. Make the area trapezoidal by fitting a new tile against the area's edge that includes an edge of Y. Fit another tile T against the smaller of the trapezoid's parallel edges.
In each case, we now have n+1 tiles, tiling an equilateral triangle with side length a(n) plus the side of T. As the sides of new and removed tiles can be calculated by adding sides of tiles that stayed in place, the GCD of the sides is unchanged.
(End)

Examples

			a(12) = 16:
                                  *
                                 / \
                                +   +
                               /     \
                              +       +
                             /         \
                            +           +
                           /             \
                          +               +
                         /                 \
                        +                   +
                       /                     \
                      +                       +
                     /                         \
                    +                           +
                   /                             \
                  +                               +
                 /                                 \
                *---+---*---+---+---+---+---+---+---*
               / \     / \                         / \
              +   +   +   +                       +   +
             /     \ /     \                     /     \
            *---*---*       +                   +       +
           / \ / \ /         \                 /         \
          +   *---*---+---+---*               +           +
         /     \             / \             /             \
        +       +           +   +           +               +
       /         \         /     \         /                 \
      +           +       +       +       +                   +
     /             \     /         \     /                     \
    +               +   +           +   +                       +
   /                 \ /             \ /                         \
  *---+---+---+---+---*---+---+---+---*---+---+---+---+---+---+---*
		

Crossrefs

A014529 gives greatest area of any convex polygon constructable from such triangles.
A089047 is this sequence's equivalent for squares.

Extensions

Definition modified and 5 terms prepended by Peter Munn, Mar 14 2018

A300001 Side length of the smallest equilateral triangle that can be dissected into n equilateral triangles with integer sides, or 0 if no such triangle exists.

Original entry on oeis.org

1, 0, 0, 2, 0, 3, 4, 4, 3, 4, 5, 6, 4, 5, 6, 4, 5, 6, 5, 6, 6, 5, 7, 6, 5, 7, 6, 6, 7, 6, 7, 7, 6, 7, 7, 6, 7, 7, 8, 7, 7, 8, 7, 8, 8, 7, 8, 8, 7, 8, 9, 8, 8, 9, 8, 8, 9, 8, 9, 9, 8, 9, 9, 8, 9, 9, 9, 10, 9, 9, 10, 9, 9, 10, 9, 10, 10, 9, 10, 10, 9, 10, 10, 10, 10, 10, 11, 10, 10, 11, 10, 10, 11, 10, 11, 11, 10, 11, 11, 10
Offset: 1

Views

Author

Hugo Pfoertner, Feb 20 2018

Keywords

Comments

No solutions exist for n = 2, 3 and 5.
a(n) = A290820(n) for n <= 8. It is conjectured that a(n) < A290820(n) for all n > 12.
The seven numbers mentioned by Peter Munn in the Formula section [1, 2, 4, 5, 7, 10, 13] coincide with the seven terms of A123120. - M. F. Hasler and Omar E. Pol, Feb 23 2018

Examples

			            a(9)=3               a(10)=4                a(11)=5
              *                     *                      *
             / \                   / \                    / \
            *---*                 *---*                  +   +
           / \ / \               / \ / \                /     \
          *---*---*             *---*---*              +       +
         / \ / \ / \           / \ / \ / \            /         \
        *---*---*---*         +   *---*   +          *---+---+---*
                             /     \ /     \        / \ / \     / \
                            *---+---*---+---*      *---*---*   +   +
                                                  / \ / \ / \ /     \
                                                 *---*---*---*---+---*
.
           a(12)=6                a(13)=4                a(14)=5
              *                      *                      *
             / \                    / \                    / \
            *---*                  *---*                  +   +
           / \ / \                / \ / \                /     \
          *---*---*              *---*---*              +       +
         / \ / \ / \            / \ / \ / \            /         \
        *---*---*---*          *---*   *---*          *---+---+---*
       / \         / \        / \ /     \ / \        / \ / \ / \ / \
      *   +       +   +      *---*---*---*---*      *---*---*---*   +
     /     \     /     \                           / \ / \ / \ /     \
    +       +   +       +                         *---*---*---*---+---*
   /         \ /         \
  *---+---+---*---+---+---*
.
           a(15)=6                 a(16)=4                a(17)=5
              *                       *                      *
             / \                     / \                    / \
            +   +                   *---*                  +   +
           /     \                 / \ / \                /     \
          +       +               *---*---*              +       +
         /         \             / \ / \ / \            /         \
        +           +           *---*---*---*          *---*---*---*
       /             \         / \ / \ / \ / \        / \ / \ / \ / \
      *---*---*---*---*       *---*---*---*---*      *---*---*---*---*
     / \     / \     / \                            / \ / \ / \ / \ / \
    *---*   *---*   *---*                          *---*---*---*---*---*
   / \ / \ / \ / \ / \ / \
  *---*---*---*---*---*---*
.
           a(18)=6                 a(19)=5                 a(20)=6
              *                       *                       *
             / \                     / \                     / \
            +   +                   +   +                   *---*
           /     \                 /     \                 / \ / \
          +       +               *---*---*               *---*---*
         /         \             / \     / \             / \ / \ / \
        +           +           *---*   *---*           *---*---*---*
       /             \         / \ / \ / \ / \         / \ / \ / \ / \
      *---*---*---*---*       *---*---*---*---*       +   *---*---*   +
     / \ / \ / \ / \ / \     / \ / \ / \ / \ / \     /     \ / \ /     \
    *---*---*   *---*---*   *---*---*---*---*---*   +       *---*       +
   / \ / \ /     \ / \ / \                         /         \ /         \
  *---*---*---+---*---*---*                       *---+---+---*---+---+---*
		

Crossrefs

Formula

a(n^2) = n for all n>=1, a(n^2-3) = n for all n>=3. - Corrected by Peter Munn, Feb 24 2018
For n > 23, if A068527(n) = 1, 2, 4, 5, 7, 10 or 13 then a(n) = ceiling(sqrt(n)) + 1 else a(n) = ceiling(sqrt(n)). - Peter Munn, Feb 23 2018

Extensions

a(21)-a(100) from Peter Munn, Feb 24 2018

A358715 a(n) is the number of distinct ways to cut an equilateral triangle with edges of size n into equilateral triangles with integer sides.

Original entry on oeis.org

1, 2, 5, 26, 220, 3622, 105859, 5677789, 553715341, 98404068313, 31850967186980, 18779046566454536, 20167518569123722322, 39451359692134386945019
Offset: 1

Views

Author

Craig Knecht and John Mason, Nov 28 2022

Keywords

Comments

In other words, the number of equilateral triangular tilings of an equilateral triangle, where rotations and reflections are considered distinct.

Examples

			a(3)=5 because of:
    /\      /\      /\      /\      /\
   /  \    /\/\    /  \    /\/\    /\/\
  /    \  /  \/\  /\/\/\  /\/  \  /\/\/\
		

Crossrefs

Extensions

a(10)-a(14) from Walter Trump, Dec 03 2022
Showing 1-3 of 3 results.