cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A292313 Numbers that are the sum of three squares in arithmetic progression.

Original entry on oeis.org

75, 300, 507, 675, 867, 1200, 1875, 2028, 2523, 2700, 3468, 3675, 4107, 4563, 4800, 5043, 6075, 7500, 7803, 8112, 8427, 9075, 10092, 10800, 11163, 12675, 13872, 14700, 15987, 16428, 16875, 18252, 19200, 20172, 21675, 22707, 23763, 24300, 24843, 27075, 28227, 30000, 30603
Offset: 1

Views

Author

Antonio Roldán, Sep 14 2017

Keywords

Examples

			75 = 1^2 + 5^2 + 7^2 = 1 + 25 + 49, with 25 - 1 = 49 - 25 = 24.
675 = 3^2 + 15^2 + 21^2 = 9 + 225 + 441, with 225 - 9 = 441 - 225 = 216.

Links

Crossrefs

Subsequence of A033428.
Cf. A000290, A000378, A004431, A134422, A292309, A292310, A292314, A292316.

Programs

  • PARI
    t=4; k=3; while(t<=13000, i=k; e=0; v=t+i; while(i>1&&e==0, if(issquare(v), m=3*t; e=1; print1(m,", ")); i+=-2; v+=i); k+=2; t+=k)

Formula

Sequence is 3*(distinct elements in A198385).
Numbers of the form 3*m^2 where 2*m^2 is in A004431. - Chai Wah Wu, Oct 05 2017

A292309 Numbers equal to the sum of three triangular numbers in arithmetic progression.

Original entry on oeis.org

9, 63, 84, 108, 234, 315, 459, 513, 570, 630, 759, 975, 1053, 1134, 1395, 1584, 1998, 2109, 2709, 2838, 2970, 3105, 3384, 3528, 3825, 4134, 4455, 4620, 4788, 4959, 5133, 5310, 5673, 5859, 6834, 7038, 7668, 7884, 8325, 8778, 9009, 9243, 9480, 10209, 10710, 11223
Offset: 1

Views

Author

Antonio Roldán, Sep 14 2017

Keywords

Comments

Subsequence of A045943, because a(n) = 3*k*(k+1)/2 = 3*A000217(k) for some k.

Examples

			9 = A000217(0) + A000217(2) + A000217(3) = 0 + 3 + 6, with 6 - 3 = 3 - 0 = 3.
513 = A000217(11) + A000217(18) + A000217(23) = 66 + 171 + 276, with 171 - 66 = 276 - 171 = 105.

Crossrefs

Cf. A000217, A045943, A127329, A292310, A292313, A292314, A292316.

Programs

  • Mathematica
    Module[{t = 3, k = 2, i, e, v, m}, Reap[While[t <= 5000, i = k; e = 0; v = t+i; While[i > 0 && e == 0, If[IntegerQ @ Sqrt[8v+1], m = 3t; e = 1; Sow[m]]; i--; v += i]; k++; t += k]][[2, 1]]] (* Jean-François Alcover, Jun 25 2023, after PARI code *)
  • PARI
    t=3;k=2;while(t<=5000,i=k;e=0;v=t+i;while(i>1&&e==0,if(issquare(8*v+1),m=3*t;e=1;print1(m,", "));i+=-1;v+=i);k+=1;t+=k)

Formula

a(n) = 3*A292310(n).

A292310 Triangular numbers that are equidistant from two other triangular numbers.

Original entry on oeis.org

3, 21, 28, 36, 78, 105, 153, 171, 190, 210, 253, 325, 351, 378, 465, 528, 666, 703, 903, 946, 990, 1035, 1128, 1176, 1275, 1378, 1485, 1540, 1596, 1653, 1711, 1770, 1891, 1953, 2278, 2346, 2556, 2628, 2775, 2926, 3003, 3081, 3160, 3403, 3570, 3741, 3828, 4095, 4186, 4278, 4371, 4656
Offset: 1

Views

Author

Antonio Roldán, Sep 14 2017

Keywords

Comments

Triangular numbers which are the arithmetic mean of two other triangular numbers. - R. J. Mathar, Oct 01 2017

Examples

			3 is in the sequence because 0 = A000217(0), 6 = A000217(3), and the distances from 3 to 0 and 3 to 6 are the same.
153 is in the sequence because 153 = A000217(17), 6 = A000217(2), 300 = A000217(24), and the two distances 300-153 = 153-6 = 147 are the same.

Crossrefs

Cf. A000217, A292309, A292313, A292314, A292316.

Programs

  • Maple
    isA292310 := proc(n)
    local ilow ;
    if isA000217(n) then
        for ilow from 0 do
            tilow := A000217(ilow) ;
            if tilow >= n then
                return false ;
            elif isA000217(2*n-tilow) then
                return true ;
            end if;
        end do:
    else
        false;
    end if;
end proc:
for n from 1 to 5000 do
    if isA292310(n) then
        printf("%d,",n) ;
    end if;
end do: # R. J. Mathar, Oct 01 2017
  • Mathematica
    Module[{t = 3, k = 2, i, e, v}, Reap[While[t <= 6000, i = k; e = 0; v = t + i; While[i > 0 && e == 0, If[IntegerQ@Sqrt[8v + 1], e = 1; Sow[t]]; i--; v += i]; k++; t += k]][[2, 1]]] (* Jean-François Alcover, Jun 25 2023, after first PARI code *)
  • PARI
    t=3; k=2; while(t<=6000, i=k; e=0; v=t+i; while(i>0&&e==0, if(issquare(8*v+1), e=1; print1(t,", ")); i--; v+=i); k++; t+=k)
  • PARI
    upto(n) = {my(t = 0, i = 0, triangulars = List([0]), res = List); while(t <= n, i++; t+=i; listput(triangulars, t)); for(i=2,#triangulars, tr = triangulars[i]<<1; for(j = 1, i-1, if(issquare(8 * (tr - triangulars[j]) + 1), listput(res, triangulars[i]); next(2)))); res} \\ David A. Corneth, Oct 04 2017

Formula

a(n) = A292309(n)/3.

Extensions

Term 105 added by David A. Corneth, Oct 04 2017

A292314 Numbers equal to the sum of three oblong numbers in arithmetic progression.

Original entry on oeis.org

18, 126, 168, 216, 468, 918, 1026, 1140, 1260, 1518, 1950, 2106, 2268, 2790, 3168, 3996, 4218, 5418, 5676, 5940, 6210, 6768, 7056, 7650, 8268, 8910, 9240, 9576, 9918, 10266, 10620, 11346, 11718, 13668, 14076, 15336, 15768, 16650, 17556, 18018, 18486, 18960, 20418, 21420, 22446
Offset: 1

Views

Author

Antonio Roldán, Sep 14 2017

Keywords

Comments

Subsequence of A028896.

Examples

			126 = 3*4 + 6*7 + 8*9 = 12 + 42 + 72, with 72 - 42 = 42 - 12 = 30;
468 = 8*9 + 12*13 + 15*16 = 72 + 156 + 240, with 240 - 156 = 156 - 72 = 84.

Crossrefs

Cf. A292309, A292310, A292313, A292316.

Programs

  • Mathematica
    o[n_] := n(n+1); s[x_] := Reduce[ x+k == o[y] && x-k == o[z] && k>0 && z>0, {z, y, k}, Integers]; 3 Select[o@ Range@ 93, s[#] =!= False &] (* Giovanni Resta, Sep 18 2017 *)
  • PARI
    t=2; k=2; while(t<=10^4, i=k; e=0; v=t+i; while(i>2&&e==0, if(issquare(4*v+1), m=3*t; e=1; print1(m,", ")); i+=-2; v+=i); k+=2; t+=k)

Formula

a(n) = 3*A292316(n).
Showing 1-4 of 4 results.

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