A292556 Number of rooted unlabeled trees on n nodes where each node has at most 11 children.
1, 1, 1, 2, 4, 9, 20, 48, 115, 286, 719, 1842, 4766, 12485, 32970, 87802, 235355, 634771, 1720940, 4688041, 12824394, 35216524, 97039824, 268238379, 743596131, 2066801045, 5758552717, 16080588286, 44997928902, 126160000878, 354349643101, 996946927831
Offset: 0
Keywords
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..1000
- Marko Riedel, Trees with bounded degree.
Crossrefs
Programs
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Maple
b:= proc(n, i, t, k) option remember; `if`(n=0, 1, `if`(i<1, 0, add(binomial(b((i-1)$2, k$2)+j-1, j)* b(n-i*j, i-1, t-j, k), j=0..min(t, n/i)))) end: a:= n-> `if`(n=0, 1, b(n-1$2, 11$2)): seq(a(n), n=0..35); # Alois P. Heinz, Sep 20 2017
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Mathematica
b[n_, i_, t_, k_] := b[n, i, t, k] = If[n == 0, 1, If[i<1, 0, Sum[Binomial[ b[i-1, i-1, k, k]+j-1, j]*b[n-i*j, i-1, t-j, k], {j, 0, Min[t, n/i]}]]]; a[n_] := If[n == 0, 1, b[n-1, n-1, 11, 11]]; Table[a[n], {n, 0, 35}] (* Jean-François Alcover, Jun 05 2018, after Alois P. Heinz *)
Formula
Functional equation of g.f. is T(z) = z + z*Sum_{q=1..11} Z(S_q)(T(z)) with Z(S_q) the cycle index of the symmetric group.
Alternate FEQ is T(z) = 1 + z*Z(S_11)(T(z)).
a(n) = Sum_{j=1..11} A244372(n,j) for n > 0, a(0) = 1. - Alois P. Heinz, Sep 20 2017
Limit_{n->oo} a(n)/a(n+1) = 0.338324339068091181557475416836618315086769320447748735003402... - Robert A. Russell, Feb 11 2023