cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A309893 Decimal expansion of AGM(1, sqrt(3)/2).

Original entry on oeis.org

9, 3, 1, 8, 0, 8, 3, 9, 1, 6, 2, 2, 4, 4, 8, 2, 7, 1, 1, 7, 7, 8, 4, 4, 5, 1, 5, 5, 1, 2, 1, 3, 5, 2, 9, 7, 5, 7, 8, 7, 6, 6, 4, 2, 8, 4, 1, 3, 4, 2, 6, 8, 6, 1, 1, 1, 0, 2, 2, 0, 6, 1, 3, 4, 8, 9, 1, 6, 2, 8, 9, 7, 2, 8
Offset: 0

Views

Author

Daniel Hoyt, Aug 21 2019

Keywords

Comments

Related to the pendulum acceleration relation at 60 degrees. In general, the period T of a mathematical pendulum with a maximum deflection angle theta is 2*Pi*sqrt(L/g)/AGM(1, cos(theta/2)), where L is the length of the pendulum, g is the gravitational acceleration, and 0 < theta <= 90 degrees. For theta = 60 degrees, the period is T = 2*Pi*sqrt(L/g)/AGM(1, sqrt(3)/2). - Jianing Song, Nov 21 2022

Examples

			0.931808391622448271177844...
		

Crossrefs

Cf. A310000 (AGM(1, cos(Pi/5))), A096427 (AGM(1, sqrt(2)/2)), A053004, A014549, A068521.

Programs

  • Mathematica
    RealDigits[ArithmeticGeometricMean[1, Sqrt[3]/2], 10, 100][[1]] (* Amiram Eldar, Aug 21 2019 *)
  • PARI
    agm(1, sqrt(3)/2) \\ Michel Marcus, Aug 22 2019
    
  • Python
    import decimal
    prec = int(input('Precision: '))
    decimal.getcontext().prec = prec
    D = decimal.Decimal
    def agm(a, b):
        for x in range(prec):
            a, b = (a + b) / 2,(a * b).sqrt()
        return a
    print(agm(1, D(3).sqrt()/2))
    
  • Sage
    RealField(300)(1.0).agm(sqrt(3)/2) # Peter Luschny, Aug 22 2019

Formula

AGM(1, sin(Pi/3)).

A376643 Decimal expansion 4*EllipticK(4/5)/sqrt(5), where EllipticK is the complete elliptic integral of the first kind.

Original entry on oeis.org

4, 0, 3, 7, 8, 1, 1, 6, 3, 9, 9, 5, 6, 8, 4, 6, 4, 3, 1, 1, 6, 8, 0, 2, 8, 8, 7, 9, 9, 9, 7, 8, 6, 4, 9, 3, 0, 1, 3, 6, 0, 8, 3, 9, 9, 3, 4, 0, 8, 8, 0, 6, 8, 5, 7, 8, 6, 3, 4, 9, 6, 1, 5, 9, 8, 9, 7, 7, 7, 3, 8, 3, 7, 8, 6, 5, 3, 1, 9, 4, 7, 4, 4, 4, 0, 7, 7, 0, 1, 5, 0, 7, 0, 3, 3, 7, 9, 1, 9, 6, 9, 1, 0, 5, 7
Offset: 1

Views

Author

Amiram Eldar, Oct 01 2024

Keywords

Comments

A point mass is attached to a frictionless pivot by a massless string of length L and revolves in a vertical circle about the pivot in a uniform gravitational field with an acceleration g. The slowest possible motion occurs when the tension in the string is momentarily zero at the top of the route, and the longest-possible period is then c * sqrt(L/g), where c is this constant.

Examples

			4.03781163995684643116802887999786493013608399340880...
		

Crossrefs

Constants related to similar physical problems: A019692, A038533, A038534, A175574, A256514, A309893, A310000.

Programs

  • Mathematica
    RealDigits[4 * EllipticK[4/5] / Sqrt[5], 10, 120][[1]]
  • PARI
    4*ellK(sqrt(4/5))/sqrt(5)

Formula

Equals 2 * Integral_{0..Pi} (1/sqrt(3 + 2*cos(x))) dx.
Showing 1-2 of 2 results.