A317749 a(n+1) = d(n) + d(a(n)) with a(1)=1, where d(n) is the number of the divisors of n.
1, 2, 4, 5, 5, 4, 7, 4, 7, 5, 6, 6, 10, 6, 8, 8, 9, 5, 8, 6, 10, 8, 8, 6, 12, 9, 7, 6, 10, 6, 12, 8, 10, 8, 8, 8, 13, 4, 7, 6, 12, 8, 12, 8, 10, 10, 8, 6, 14, 7, 8, 8, 10, 6, 12, 10, 12, 10, 8, 6, 16, 7, 6, 10, 11, 6, 12, 8, 10, 8, 12, 8, 16, 7, 6, 10, 10, 8, 12, 8, 14, 9, 7, 4, 15, 8, 8, 8, 12, 8, 16, 9, 9, 7, 6, 8, 16, 7, 8, 10
Offset: 1
Keywords
Examples
d(1) = 1, d(2) = 2, d(3) = 2; a(1) = 1, a(2) = 2, a(3) = 4. a(38)=4, so 37 and a(37)=13 are prime numbers.
Links
- Robert G. Wilson v, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
a[n_] := DivisorSigma[0, n - 1] + DivisorSigma[0, a[n - 1]]; a[1] = 1; Array[a, 80] (* Robert G. Wilson v, Aug 06 2018 *)
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PARI
a(n) = if (n==1, 1, numdiv(n-1) + numdiv(a(n-1))); \\ Michel Marcus, Aug 25 2018
Formula
a(n+1) = d(n) + d(a(n)) where d(n) is the number of divisors of n (A000005).
Extensions
Name edited by and more terms from Robert G. Wilson v, Aug 06 2018
Comments