cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A356125 a(n) = Sum_{k=1..n} k * sigma_2(k).

Original entry on oeis.org

1, 11, 41, 125, 255, 555, 905, 1585, 2404, 3704, 5046, 7566, 9776, 13276, 17176, 22632, 27562, 35752, 42630, 53550, 64050, 77470, 89660, 110060, 126335, 148435, 170575, 199975, 224393, 263393, 293215, 336895, 377155, 426455, 471955, 540751, 591441, 660221, 726521
Offset: 1

Views

Author

Seiichi Manyama, Jul 27 2022

Keywords

Crossrefs

Partial sums of A328259.
Column k=3 of A356124.

Programs

  • Mathematica
    a[n_] := Sum[k * DivisorSigma[2, k], {k, 1, n}]; Array[a, 39] (* Amiram Eldar, Jul 28 2022 *)
  • PARI
    a(n) = sum(k=1, n, k*sigma(k, 2));
    
  • PARI
    a(n) = sum(k=1, n, k^3*binomial(n\k+1, 2));
    
  • PARI
    my(N=40, x='x+O('x^N)); Vec(sum(k=1, N, k^3*x^k/(1-x^k)^2)/(1-x))
    
  • Python
    from math import isqrt
    def A356125(n): return (-((s:=isqrt(n))*(s+1))**3>>1) + sum(k*(q:=n//k)*(q+1)*(2*k**2+q*(q+1)) for k in range(1,s+1))>>2 # Chai Wah Wu, Oct 21 2023

Formula

a(n) = Sum_{k=1..n} k^3 * binomial(floor(n/k)+1,2).
G.f.: (1/(1-x)) * Sum_{k>=1} k^3 * x^k/(1 - x^k)^2.
a(n) ~ zeta(3) * n^4 / 4. - Vaclav Kotesovec, Aug 02 2022

A356249 a(n) = Sum_{k=1..n} (k * floor(n/k))^3.

Original entry on oeis.org

1, 16, 62, 219, 405, 1053, 1523, 2948, 4407, 7041, 8703, 15283, 17949, 24657, 32685, 44806, 50536, 70687, 78573, 105411, 125879, 149879, 163565, 222425, 247476, 286134, 327634, 396258, 423084, 532236, 564818, 664763, 738095, 821693, 904937, 1107618, 1162268, 1277588, 1395760
Offset: 1

Views

Author

Seiichi Manyama, Jul 31 2022

Keywords

Crossrefs

Programs

  • Mathematica
    a[n_] := Sum[(k * Floor[n/k])^3, {k, 1, n}]; Array[a, 40] (* Amiram Eldar, Jul 31 2022 *)
  • PARI
    a(n) = sum(k=1, n, (k*(n\k))^3);
    
  • PARI
    a(n) = sum(k=1, n, k^3*sumdiv(k, d, 1-(1-1/d)^3));
    
  • PARI
    my(N=40, x='x+O('x^N)); Vec(sum(k=1, N, (k^3-(k-1)^3)*x^k*(1+4*x^k+x^(2*k))/(1-x^k)^4)/(1-x))
    
  • Python
    from math import isqrt
    def A356249(n): return -(s:=isqrt(n))**5*(s+1)**2 + sum((q:=n//k)**2*(k*(3*(k-1))+q*(k*(k*(4*k+6)-6)+q*(k*(3*(k-1))+1)+2)+1) for k in range(1,s+1))>>2 # Chai Wah Wu, Oct 21 2023

Formula

a(n) = Sum_{k=1..n} k^3 * Sum_{d|k} (1 - (1 - 1/d)^3).
G.f.: (1/(1 - x)) * Sum_{k>=1} (k^3 - (k - 1)^3) * x^k * (1 + 4*x^k + x^(2*k))/(1 - x^k)^4.
From Vaclav Kotesovec, Aug 02 2022: (Start)
a(n) = A064603(n) - 3*A356125(n) + 3*A319086(n).
a(n) ~ n^4 * (Pi^2/8 + Pi^4/360 - 3*zeta(3)/4). (End)

A364194 a(n) = Sum_{k=1..n} k^3*sigma(k), where sigma is A000203.

Original entry on oeis.org

1, 25, 133, 581, 1331, 3923, 6667, 14347, 23824, 41824, 57796, 106180, 136938, 202794, 283794, 410770, 499204, 726652, 863832, 1199832, 1496184, 1879512, 2171520, 3000960, 3485335, 4223527, 5010847, 6240159, 6971829, 8915829, 9869141, 11933525, 13658501
Offset: 1

Views

Author

Seiichi Manyama, Oct 20 2023

Keywords

Crossrefs

Partial sums of A282211.

Programs

  • Mathematica
    Accumulate[Table[n^3*DivisorSigma[1, n], {n, 1, 33}]] (* Amiram Eldar, Oct 20 2023 *)
  • PARI
    f(n, m) = (subst(bernpol(m+1, x), x, n+1)-subst(bernpol(m+1, x), x, 0))/(m+1);
    a(n, s=3, t=1) = sum(k=1, n, k^(s+t)*f(n\k, s));
    
  • Python
    def A364194(n): return sum((k**2*(m:=n//k)*(m+1)>>1)**2 for k in range(1,n+1)) # Chai Wah Wu, Oct 20 2023
    
  • Python
    from math import isqrt
    def A364194(n): return ((((s:=isqrt(n))*(s + 1))**3*(2*s+1)*(1-3*s*(s+1))>>1) + sum((q:=n//k)*(q+1)*k**3*(q*(15*k+q*(15*k+12*q+18)+2)-2) for k in range(1,s+1)))//60 # Chai Wah Wu, Oct 21 2023

Formula

a(n) = Sum_{k=1..n} k^4 * A000537(floor(n/k)).
a(n) ~ (zeta(2)/5) * n^5. - Amiram Eldar, Oct 20 2023
Showing 1-3 of 3 results.