A323501 Number of minimum dominating sets in the n X n white bishop graph.
2, 6, 5, 2, 22, 356, 108, 24, 672, 25056, 4680, 720, 38160, 2531520, 342720, 40320, 3467520, 358444800, 38102400, 3628800, 460857600, 68388364800, 5987520000, 479001600, 84304281600, 16979648716800, 1264085222400, 87178291200, 20312541849600
Offset: 2
Keywords
Links
- Andrew Howroyd, Table of n, a(n) for n = 2..50
- Eric Weisstein's World of Mathematics, Minimum Dominating Set
- Eric Weisstein's World of Mathematics, White Bishop Graph
Programs
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Mathematica
Table[Piecewise[{{(n/2)! (n + 1)/2, Mod[n, 4] == 0}, {((n - 1)/2)!, Mod[n, 4] == 1}, {(n/2 - 1)! (n^2 + n + 2)/4, Mod[n, 4] == 2}, {((n - 3)/2)! (n + 1) (n^3 + n^2 - 6 n + 6)/16, Mod[n, 4] == 3}}], {n, 2, 20}] (* Eric W. Weisstein, Feb 27 2025 *)
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PARI
\\ See A289170 for DomSetCount, Bishop. a(n)={Vec(DomSetCount(Bishop(n, 1), x + O(x^((n+3)\2))))[1]} \\ Andrew Howroyd, Sep 08 2019
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PARI
a(n)=(n\4*2)!*if(n%4<2, if(n%2==0, (n + 1)/2, 1), if(n%2==0, (n^2 + n + 2)/4, (n + 1)*(n^3 + n^2 - 6*n + 6)/16)); \\ Andrew Howroyd, Sep 09 2019
Formula
From Andrew Howroyd, Sep 09 2019: (Start)
a(n) = (n/2)! * (n + 1)/2 for n mod 4 = 0;
a(n) = ((n-1)/2)! for n mod 4 = 1;
a(n) = (n/2-1)! * (n^2 + n + 2)/4 for n mod 4 = 2;
a(n) = ((n-3)/2)! * (n + 1)*(n^3 + n^2 - 6*n + 6)/16 for n mod 4 = 3.
(End)
Extensions
Offset corrected and terms a(11) and beyond from Andrew Howroyd, Sep 08 2019