A328339 Simple continued fraction expansion of Gamma(exp(gamma)+1).
1, 1, 1, 1, 6, 15, 1, 4, 2, 1, 11, 2, 3, 1, 1, 13, 1, 1, 1, 1, 5, 1, 27, 1, 37, 1, 1, 2, 2, 2, 40, 1, 3, 1, 5, 1, 1, 3, 3942, 3, 2, 1, 13, 3, 11, 1, 2, 1, 15, 1, 1, 2, 1, 51, 37, 1, 1, 13, 4, 1, 1, 2, 5, 1, 1, 2, 1, 1, 5, 1, 75, 1, 16, 6, 2, 2, 1, 1, 7, 2, 4
Offset: 0
Programs
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Mathematica
ContinuedFraction[Gamma[1 + Exp[EulerGamma]], 81] (* Amiram Eldar, Oct 13 2019 *)
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PARI
contfrac(gamma(exp(Euler)+1)) \\ Michel Marcus, Nov 04 2019
Formula
Gamma(exp(gamma)+1) = Gamma(exp(gamma)) * exp(gamma).
Comments