A333240 Decimal expansion of Product_{primes p == 2 (mod 3)} 1/(1 - 1/p^2).
1, 4, 1, 4, 0, 6, 4, 3, 9, 0, 8, 9, 2, 1, 4, 7, 6, 3, 7, 5, 6, 5, 5, 0, 1, 8, 1, 9, 0, 7, 9, 8, 2, 9, 3, 7, 9, 9, 0, 7, 6, 9, 5, 0, 6, 9, 3, 9, 3, 1, 6, 2, 1, 7, 5, 0, 3, 9, 9, 2, 4, 9, 6, 2, 4, 2, 3, 9, 2, 8, 1, 0, 6, 9, 9, 2, 0, 8, 8, 4, 9, 9, 4, 5, 3, 7, 5, 4, 8, 5, 8, 5, 0, 2, 4, 7, 5, 1, 1, 4, 2, 0, 0, 2
Offset: 1
Examples
1.414064390892147637565501819079829379907695069393162175039924962423928106992...
Links
- Peter Luschny, Table of n, a(n) for n = 1..1000
- Thomas Dence and Carl Pomerance, Euler's Function in Residue Classes, Raman. J., Vol. 2 (1998) pp. 7-20, c_3 in formula (1.8) and (5.6), alternative link.
- S. Ettahri, O. Ramare, L. Surel, Fast multi-precision computation of some Euler products, arxiv:1908.06808 (2019), Section 9.
- Jerzy Kaczorowski, Waldemar Ratajczak, Peter Nijkamp, Krzysztof Górnisiewicz, Economic hierarchical spatial systems - new properties of Löschian numbers, Applied Mathematics and Computation, Volume 461 (2024) 128319. (The product appears in Theorem 3 (12)).
- R. J. Mathar, Table of Dirichlet L-series and prime zeta modulo functions for small moduli, arXiv:1008.2547 [math.NT], 2010-2015, Zeta_{3,2}(2) in section 3.2.
Programs
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Maple
z := n -> Zeta(n)/Im(polylog(n, (-1)^(2/3))): x := n -> (z(2^n)*(3^(2^n)-1)*sqrt(3)/2)^(1/2^n)/3: evalf(mul(x(n), n=1..8), 105); # Peter Luschny, Jan 17 2021
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Mathematica
digits = 104; precision = digits + 10; prodeuler[p_, a_, b_, expr_] := Product[If[a <= p <= b, expr, 1], {p, Prime[Range[PrimePi[a], PrimePi[b]]]}]; Lv3[s_] := prodeuler[p, 1, 2^(precision/s), 1/(1 - KroneckerSymbol[-3, p]*p^-s)] // N[#, precision]&; Lv4[s_] := 2*Im[PolyLog[s, Exp[2*I*Pi/3]]]/Sqrt[3]; Lv[s_] := If[s >= 10000, Lv3[s], Lv4[s]]; gv[s_] := (1 - 3^(-s))*Zeta[s]/Lv[s]; pgv = Product[gv[2^n*2]^(2^-(n + 1)), {n, 0, 11}] // N[#, precision]&; RealDigits[pgv, 10, digits][[1]] (* Jean-François Alcover, Jan 12 2021, after PARI code due to Artur Jasinski *) z[n_] := Zeta[n]/Im[PolyLog[n, (-1)^(2/3)]]; x[n_] := (z[2^n] (3^(2^n) - 1) Sqrt[3]/2)^(1/2^n)/3; N[Product[x[n], {n, 8}], 105] (* Peter Luschny, Jan 17 2021 *)
Formula
Extensions
Last 5 digits corrected by Jean-François Alcover, Jan 12 2021
Better name by Peter Luschny, Jan 17 2021
Comments