cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A335184 a(n) is the number of subsets of {1,2,...,n} with at least two elements and the difference between successive elements at least 6.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 1, 3, 6, 10, 15, 21, 29, 40, 55, 75, 101, 134, 176, 230, 300, 391, 509, 661, 856, 1106, 1427, 1840, 2372, 3057, 3938, 5070, 6524, 8392, 10793, 13880, 17849, 22951, 29508, 37934, 48762, 62678, 80564, 103553, 133100, 171074, 219877, 282597, 363204, 466801, 599946, 771066, 990990
Offset: 0

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Author

Enrique Navarrete, May 25 2020

Keywords

Comments

For n >= 6 the sequence contains the triangular numbers; for n >= 12 we have to add the tetrahedral numbers; for n >= 18 we have to add the numbers binomial(n,4) (starting with 0,1,5,...); for n >= 24 we have to add the numbers binomial(n,5) (starting with 0,1,6,..); in general, for n >= 6*k we have to add to the sequence the numbers binomial(n, k+1), k >= 1.
For example, a(26) = 1106 = 210+560+330+6, where 210 is a triangular number, 560 is a tetrahedral number, 330 is a number binomial(n,4) and 6 is a number binomial(m,5) (with the proper n, m due to shifts in names of the sequences).
The sequence counts sets with more than 2 elements such as {1,7,14}, {1,8,14}, {2,8,14,20}, etc. The first 3-element set is {1,7,13}, the first 4-element set is {1,7,13,19}, etc. Every time a larger set needs to be counted is when we have to add a term binomial(n, k+1).

Examples

			a(11) = 15 and the 15 subsets of {1,2,...11} with at least two elements and whose difference between successive elements is at least 6 are: {1,7}, {1,8}, {1,9}, {1,10}, {1,11}, {2,8}, {2,9}, {2,10}, {2,11}, {3,9}, {3,10}, {3,11}, {4,10}, {4,11}, {5,11}.
		

Crossrefs

Similar sequences with minimum difference 1..5 are A000295, A001924, A050228, A145131, A330910.

Programs

Formula

a(n) = Sum_{k=0..floor((n-1)/6)} binomial(n-6*k+k+1, k+2). - Andrew Howroyd, Aug 11 2020
From Colin Barker, May 26 2020: (Start)
G.f.: x^7 / ((1 - x)^2*(1 - x - x^6)).
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) + a(n-6) - 2*a(n-7) + a(n-8) for n>=8.
(End)