cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A340695 a(n) is the next perfect power after the earliest occurrence of n consecutive perfect powers, all of which are squares with exponents equal to 2.

Original entry on oeis.org

8, 64, 216, 512, 1728, 4913, 12167, 19683, 32768, 74088, 148877, 175616, 328509, 493039, 753571, 1259712, 1860867, 2406104, 3375000, 4330747, 5929741, 8365427, 11089567, 13824000, 18191447, 23639903, 28934443, 36264691, 43614208, 53582633, 67917312, 81182737, 97972181
Offset: 1

Views

Author

Hugo Pfoertner, Jan 18 2021

Keywords

Comments

The exponent of a(n) is > 2 thus terminating the progression of n consecutive preceding squares with exponents = 2 (A111245).
Is this sequence strictly increasing? - David A. Corneth, Jan 19 2021

Examples

			See A340661.
From _David A. Corneth_, Jan 19 2021: (Start)
a(3) = 216 as in the perfect powers we see ..., 128 = 2^7, 144 = 12^2, 169 = 13^2, 196 = 14^2, 216 = 6^3, ... . We write them as powers of m^k where k is chosen as large as possible such that m and k are integers.
Then between two perfect powers with k > 2 (being 128 = 2^7 and 216 = 6^3) we have three consecutive perfect powers with k = 2. As 216 closes this earliest streak of 3, a(3) = 216. (End)
		

Crossrefs

Programs

  • PARI
    \\ See Corneth link

A340661 a(n) is the start of the first occurrence of n consecutive perfect powers, all of which are squares with exponents equal to 2 (A111245).

Original entry on oeis.org

4, 36, 144, 361, 1369, 4225, 10816, 17689, 29929, 69169, 140625, 166464, 314721, 474721, 729316, 1225449, 1817104, 2353156, 3308761, 4251844, 5832225, 8242641, 10942864, 13653025, 17986081, 23396569, 28654609, 35940025, 43243776, 53158681, 67420521, 80622441, 97337956
Offset: 1

Views

Author

Hugo Pfoertner, Jan 18 2021

Keywords

Examples

			Table of initial terms of a(n), A340662, A340663, A340664, and A340695:
    bounded below by       n consecutive squares       terminated by
         |             a(n)          A340662(n)           A340695(n)
  n      |               |  A340663(n)^2  |  A340664(n)^2   |
  1      1 =  1^(>2),    4 =   2^2         4 =   2^2,       8 =  2^ 3
  2     32 =  2^ 5,     36 =   6^2 ...    49 =   7^2,      64 =  2^ 6
  3    128 =  2^ 7,    144 =  12^2 ...   196 =  14^2,     216 =  6^ 3
  4    343 =  7^ 3,    361 =  19^2 ...   484 =  22^2,     512 =  2^ 9
  5   1331 = 11^ 3,   1369 =  37^2 ...  1681 =  41^2,    1728 = 12^ 3
  6   4096 =  2^12,   4225 =  65^2 ...  4900 =  70^2,    4913 = 17^ 3
  7  10648 = 22^ 3,  10816 = 104^2 ... 12100 = 110^2,   12167 = 23^ 3
  8  17576 = 26^ 3,  17689 = 133^2 ... 19600 = 140^2,   19683 =  3^ 9
  9  29791 = 31^ 3,  29929 = 173^2 ... 32761 = 181^2,   32768 =  2^15
		

Crossrefs

Formula

a(n) = A340663(n)^2.

A340662 a(n) is the end of the first occurrence of n consecutive perfect powers, all of which are squares with exponents equal to 2 (A111245).

Original entry on oeis.org

4, 49, 196, 484, 1681, 4900, 12100, 19600, 32761, 73984, 148225, 175561, 328329, 492804, 753424, 1258884, 1860496, 2405601, 3374569, 4330561, 5929225, 8363664, 11088900, 13823524, 18190225, 23639044, 28933641, 36264484, 43612816, 53582400, 67914081, 81180100, 97970404
Offset: 1

Views

Author

Hugo Pfoertner, Jan 18 2021

Keywords

Examples

			See A340661.
		

Crossrefs

Formula

a(n) = A340664(n)^2 = A340663(n)^2 + (n - 1)*(2*A340663(n) + n - 1).

A340664 a(n)^2 is the end of the first occurrence of n consecutive perfect powers, all of which are squares with exponents equal to 2 (A111245).

Original entry on oeis.org

2, 7, 14, 22, 41, 70, 110, 140, 181, 272, 385, 419, 573, 702, 868, 1122, 1364, 1551, 1837, 2081, 2435, 2892, 3330, 3718, 4265, 4862, 5379, 6022, 6604, 7320, 8241, 9010, 9898, 10913, 12029, 12969, 14149, 15363, 16610, 17928, 19199, 20704, 22331, 23912, 25794, 27406
Offset: 1

Views

Author

Hugo Pfoertner, Jan 18 2021

Keywords

Examples

			See A340661.
		

Crossrefs

Formula

a(n) = sqrt(A340662(n)) = A340663(n) + n - 1.
Showing 1-4 of 4 results.