A347014 Expansion of e.g.f.: exp(x) / (1 - 6*x)^(1/6).
1, 2, 10, 116, 2140, 52856, 1627192, 59930480, 2568599056, 125553289760, 6892279877536, 419788155021632, 28090704069553600, 2048487353985408896, 161687913401407530880, 13733087614786273308416, 1248892148354210466595072, 121073054127693143488709120
Offset: 0
Keywords
Programs
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Maple
g:= proc(n) option remember; `if`(n<2, 1, (6*n-5)*g(n-1)) end: a:= n-> add(binomial(n, k)*g(k), k=0..n): seq(a(n), n=0..17); # Alois P. Heinz, Aug 10 2021
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Mathematica
nmax = 17; CoefficientList[Series[Exp[x]/(1 - 6 x)^(1/6), {x, 0, nmax}], x] Range[0, nmax]! Table[Sum[Binomial[n, k] 6^k Pochhammer[1/6, k], {k, 0, n}], {n, 0, 17}] Table[HypergeometricU[1/6, n + 7/6, 1/6]/6^(1/6), {n, 0, 17}]
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Maxima
a[n]:=if n<2 then n+1 else (6*n-4)*a[n-1]-6*(n-1)*a[n-2]; makelist(a[n],n,0,50); /* Tani Akinari, Sep 08 2023 */
Formula
a(n) = Sum_{k=0..n} binomial(n,k) * A008542(k).
a(n) ~ n! * exp(1/6) * 6^n / (Gamma(1/6) * n^(5/6)). - Vaclav Kotesovec, Aug 14 2021
a(n+2) = (6*n+8)*a(n+1) - 6*(n+1)*a(n). - Tani Akinari, Sep 08 2023
Comments