cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A369936 a(n) = sqrt(A369935(n)).

Original entry on oeis.org

0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
Offset: 1

Views

Author

Amiram Eldar, Feb 06 2024

Keywords

Crossrefs

Programs

  • Mathematica
    squareQ[n_] := IntegerQ[Sqrt[n]]; f[n_] := Module[{e = FactorInteger[n][[;; , 2]]}, If[AllTrue[e, squareQ], Sqrt[Max @@ e], Nothing]]; f[1] = 0; Array[f, 150]
  • PARI
    lista(kmax) = {my(e, q); print1(0, ", "); for(k = 2, kmax, e = factor(k)[, 2]; q = 1; for(i = 1, #e, if(!issquare(e[i]), q = 0; break)); if(q, print1(sqrtint(vecmax(e)), ", "))); }

Formula

Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = Sum_{k>=1} (k * (d(k) - d(k-1))) / A357016 = 1.05307232234978965366..., where d(k) = Product_{p prime} (1 - 1/p^2 + Sum_{i=2..k} (1/p^(i^2)-1/p^(i^2+1))) for k >= 1, and d(0) = 0.

A374325 The maximal exponent in the prime factorization of the numbers whose maximal exponent in their prime factorization is a square.

Original entry on oeis.org

0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 4, 4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
Offset: 1

Views

Author

Amiram Eldar, Jul 04 2024

Keywords

Comments

First differs from A369935 at n = 95.
The first occurrence of k^2, for k = 0, 1, ..., is at 1, 2, 12, 335, 42563, ..., which is the position of 2^(k^2) at A369937.

Crossrefs

Similar sequences: A374324, A374326, A374327, A374328.

Programs

  • Mathematica
    f[n_] := Module[{e = If[n == 1, 0, Max[FactorInteger[n][[;; , 2]]]]}, If[IntegerQ@ Sqrt[e], e, Nothing]]; Array[f, 200]
  • PARI
    lista(kmax) = {my(e); print1(0, ", "); for(k = 2, kmax, e = vecmax(factor(k)[, 2]); if(issquare(e), print1(e, ", ")));}

Formula

a(n) = A374326(n)^2.
a(n) = A051903(A369937(n)).
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = Sum_{k>=1} k^2 * d(k) / Sum_{k>=1} d(k) = 1.19949058780036416105..., where d(k) = 1/zeta(k^2+1) - 1/zeta(k^2) for k>=2, and d(1) = 1/zeta(2).

A372466 The maximal exponent in the prime factorization of the numbers whose number of divisors is a power of 2 (A036537).

Original entry on oeis.org

0, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 3, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 3
Offset: 1

Views

Author

Amiram Eldar, May 01 2024

Keywords

Comments

All the terms are of the form 2^k-1 (A000225).

Crossrefs

Programs

  • Mathematica
    pow2Q[n_] := n == 2^IntegerExponent[n, 2]; f[n_] := Module[{e = FactorInteger[n][[;; , 2]]}, If[AllTrue[e, pow2Q[# + 1] &], Max @@ e, Nothing]]; f[1] = 0; Array[f, 150]
  • PARI
    ispow2(n) = n >> valuation(n, 2) == 1;
    lista(kmax) = {my(e); print1(0, ", "); for(k = 2, kmax, e = factor(k)[, 2]; if(ispow2(vecprod(apply(x -> x + 1, e))), print1(vecmax(e), ", "))); }

Formula

a(n) = A051903(A036537(n)).
a(n) = 2^A372467(n) - 1.
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = (d(1) + Sum_{k>=2} (2^k-1) * (d(k) - d(k-1))) / A327839 = 1.25306367526166810834..., where d(k) = Product_{p prime} (1 - 1/p + Sum_{i=1..k} (1/p^(2^i-1)-1/p^(2^i))).
Showing 1-3 of 3 results.