cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A053254 Coefficients of the '3rd-order' mock theta function nu(q).

Original entry on oeis.org

1, -1, 2, -2, 2, -3, 4, -4, 5, -6, 6, -8, 10, -10, 12, -14, 15, -18, 20, -22, 26, -29, 32, -36, 40, -44, 50, -56, 60, -68, 76, -82, 92, -101, 110, -122, 134, -146, 160, -176, 191, -210, 230, -248, 272, -296, 320, -350, 380, -410, 446, -484, 522, -566, 612, -660, 715, -772, 830, -896, 966, -1038
Offset: 0

Views

Author

Dean Hickerson, Dec 19 1999

Keywords

Comments

In Watson 1936 the function is denoted by upsilon(q). - Michael Somos, Jul 25 2015

Examples

			G.f. = 1 - x + 2*x^2 - 2*x^3 + 2*x^4 - 3*x^5 + 4*x^6 - 4*x^7 + 5*x^8 + ...
		

References

  • George E. Andrews, The Theory of Partitions, Addison-Wesley, 1976, (Example 6, p. 29).
  • Srinivasa Ramanujan, The Lost Notebook and Other Unpublished Papers, Narosa Publishing House, New Delhi, 1988, p. 31.

Crossrefs

Other '3rd-order' mock theta functions are at A000025, A053250, A053251, A053252, A053253, A053255.

Programs

  • Mathematica
    Series[Sum[q^(n(n+1))/Product[1+q^(2k+1), {k, 0, n}], {n, 0, 9}], {q, 0, 100}]
  • PARI
    /* Continued Fraction Expansion: */
    {a(n)=local(CF); CF=1+x; for(k=0, n, CF=1/(1 + x^(n-k+1)*(1 - x^(n-k+1))*CF+x*O(x^n))); polcoeff(CF, n)} \\ Paul D. Hanna, Jul 09 2013

Formula

G.f.: nu(q) = Sum_{n >= 0} q^(n*(n+1))/((1+q)*(1+q^3)*...*(1+q^(2*n+1)))
(-1)^n*a(n) = number of partitions of n in which even parts are distinct and if k occurs then so does every positive even number less than k.
G.f.: 1/(1 + x*(1-x)/(1 + x^2*(1-x^2)/(1 + x^3*(1-x^3)/(1 + x^4*(1-x^4)/(1 + x^5*(1-x^5)/(1 + ...)))))), a continued fraction. - Paul D. Hanna, Jul 09 2013
a(2*n) = A085140(n). a(2*n + 1) = - A053253(n). - Michael Somos, Jul 25 2015
a(n) ~ (-1)^n * exp(Pi*sqrt(n/6)) / (2^(3/2)*sqrt(n)). - Vaclav Kotesovec, Jun 15 2019
From Peter Bala, Jan 03 2025: (Start)
a(n) = (-1)^n * A067357(n).
nu(-q) = Sum_{n >= 0} q^n * (1 + q)*(1 + q^3)*...*(1 + q^(2*n-1)) (Andrews, p. 29: in Example 6 take x = q and y = -q).
Conjecture: a(n) = (-1)^n * (A376628(n) + A376628(n+1)), or equivalently, (1 + q * nu(-q))/(1 + q) = Sum_{n >= 0} q^(n*(n+1))/((1 - q)*(1 - q^3)*...*(1 - q^(2*n-1))), the g.f. of A376628. (End)

A376622 G.f.: Sum_{k>=0} x^(k*(k+1)) / Product_{j=1..k} (1 - x^(2*j-1))^2.

Original entry on oeis.org

1, 0, 1, 2, 3, 4, 6, 8, 10, 14, 18, 22, 30, 38, 46, 60, 74, 90, 114, 138, 167, 206, 248, 298, 360, 430, 511, 612, 726, 854, 1014, 1192, 1396, 1644, 1918, 2236, 2610, 3032, 3516, 4076, 4714, 5436, 6274, 7220, 8288, 9522, 10906, 12476, 14270, 16282, 18556, 21138, 24038
Offset: 0

Views

Author

Vaclav Kotesovec, Sep 30 2024

Keywords

Crossrefs

Programs

  • Mathematica
    nmax=60; CoefficientList[Series[Sum[x^(k*(k+1))/Product[1-x^(2*j-1), {j, 1, k}]^2, {k, 0, Sqrt[nmax]}], {x, 0, nmax}], x]

Formula

G.f.: Sum_{k>=0} Product_{j=1..k} (x^j/(1 - x^(2*j-1)))^2.
a(n) ~ (5 - sqrt(5)) * exp(Pi*sqrt(2*n/5)) / (8*5^(3/4)*sqrt(n)).
Showing 1-2 of 2 results.