A377293 Number of days where month plus day equals n, in a non-leap year in the Gregorian calendar.

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 11, 11, 10, 10, 8, 8, 6, 6, 5, 3, 3, 1, 1

Offset: 2

Author

Manuel Biwer, Dec 27 2024

Keywords

• nonn
• dumb
• easy
• fini
• full

Comments

Sum of all terms gives 365.

Examples

			For n=4 three dates (1st of March, 2nd of February, 3rd of January) sum to n, so a(4) = 3.
		

Crossrefs

Cf. A008685.

Programs

Maple

(p-> add(coeff(p, x, i), i=2..degree(p)))(add(add(x^(i+j), j=1..
[31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][i]), i=1..12));  # Alois P. Heinz, Dec 27 2024

Mathematica

dON[d_]:=With[{d1=Take[DateList[d],3]},d1[[2]]+d1[[3]]]; Tally[dON/@DateRange[{2025,1,1},{2025,12,31}]][[;;,2]] (* Harvey P. Dale, Feb 16 2025 *)

Python

sequence = []
for year in range(2, 43):
    current_count = 0
    for month, days_in_month in zip(range(1, 13), (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)):
        for day in range(1, days_in_month + 1):
            if month + day == year:
                current_count += 1
    sequence += [current_count]