cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A380977 Triangle read by rows: T(n,m) (1<=m<=n) = number of surjections f:[n]->[m] with f(n) != f(j), j

Original entry on oeis.org

1, 0, 2, 0, 2, 6, 0, 2, 18, 24, 0, 2, 42, 144, 120, 0, 2, 90, 600, 1200, 720, 0, 2, 186, 2160, 7800, 10800, 5040, 0, 2, 378, 7224, 42000, 100800, 105840, 40320, 0, 2, 762, 23184, 204120, 756000, 1340640, 1128960, 362880, 0, 2, 1530, 72600, 932400, 5004720, 13335840, 18627840, 13063680, 3628800
Offset: 1

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Author

Manfred Boergens, Feb 10 2025

Keywords

Comments

Number of n-tuples containing all elements of [m] with a unique last element.
Consider an urn with m balls of pairwise different colors. T(n,m) is motivated by the probability p(n,m) for exactly n draws with replacement needed to obtain all colors; p(n,m)=T(n,m)/m^n. - With m fixed and n running, p(n,m) is a probability distribution. The expected number of draws needed to obtain all colors is Sum_{j=1..m} m/j. (Expected value provided by M. Shackleford.)

Examples

			The triangle T(n,m) begins:
  n\m  1 2    3     4      5       6        7        8        9      10 ...
   1:  1
   2:  0 2
   3:  0 2    6
   4:  0 2   18    24
   5:  0 2   42   144    120
   6:  0 2   90   600   1200     720
   7:  0 2  186  2160   7800   10800     5040
   8:  0 2  378  7224  42000  100800   105840    40320
   9:  0 2  762 23184 204120  756000  1340640  1128960   362880
  10:  0 2 1530 72600 932400 5004720 13335840 18627840 13063680 3628800
  ...
T(4,3)=18 is the number of 4-sequences of draws from [3] completing the covering of [3] with the last draw; these sequences are (without brackets and commas):
   1123 1213 1223 2113 2123 2213 1132 1312 1332
   3112 3132 3312 2231 2321 2331 3221 3231 3321
		

Crossrefs

Row sums give A005649(n-1) for n>=1.

Programs

  • Mathematica
    Table[m! StirlingS2[n - 1, m - 1], {n, 10}, {m, n}]//Flatten

Formula

T(n,m) = m!*S2(n-1,m-1) = m!*A048993(n-1,m-1).
T(n,m) = m*A131689(n-1,m-1).
T(n,3) = A068293(n-1), n>1.