A383666 Numbers in whose binary representation no bit (0 or 1) occurs exactly once.
3, 7, 9, 10, 12, 15, 17, 18, 19, 20, 21, 22, 24, 25, 26, 28, 31, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 48, 49, 50, 51, 52, 53, 54, 56, 57, 58, 60, 63, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86
Offset: 1
Examples
From _David A. Corneth_, May 17 2025: (Start) 3 = 11_2 is in the sequence as both the digits 0 and the digits 1 do not occur exactly once in the binary expansion. Also 3 is no power of 2 and one less than a power of 2. 6 = 101_2 is not in the sequence as the digit 0 occurs exactly once in the binary expansion. Also it can be written as 2^3 - 2^0 - 1. (End)
Links
- David A. Corneth, Table of n, a(n) for n = 1..10000
Programs
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Maple
filter:= proc(n) local L,n1,n0; L:= convert(n,base,2); n1:= convert(L,`+`); n0:= nops(L)-n1; n1 >= 2 and n0 <> 1 end proc; select(filter, [$1..1000]); # Robert Israel, May 13 2025
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Mathematica
s = Select[Range[200], DigitCount[#, 2, 0] != 1 && DigitCount[#, 2, 1] != 1 &] Map[First, RealDigits[s, 2]]
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PARI
isok(k) = my(b=binary(k)); (#select(x->(x==1), b) != 1) && (#select(x->(x==0), b) != 1); \\ Michel Marcus, May 13 2025
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PARI
is(n) = { my(v = valuation(n, 2)); if(n >> v == 1, return(0)); if(1<
> valuation(c, 2) == 1, return(0)); 1 } \\ David A. Corneth, May 17 2025 -
PARI
upto(n) = { my(res = [1..n], del = List()); for(i = 0, logint(n, 2)+1, pow2 = 1<David A. Corneth, May 17 2025
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Python
def A383666(n): def f(x): if x<=1: return n+x l, s = x.bit_length(), bin(x)[2:] if (m:=s.count('0'))>0: return n+s.index('0')-(m>1)+(l*(l-1)>>1) return n-1+(l*(l+1)>>1) m, k = n, f(n) while m != k: m, k = k, f(k) return m # Chai Wah Wu, May 21 2025
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