A386676 Triangle of denominators for rational convergents to Taylor series of 1/Gamma(x+1).
1, 1, 1, 1, 4, 4, 1, 36, 12, 9, 1, 288, 192, 288, 192, 1, 7200, 576, 1440, 2880, 1800, 1, 5400, 51840, 11520, 103680, 172800, 103680, 1, 264600, 259200, 1209600, 103680, 44800, 3628800, 2116800, 1, 33868800, 58060800, 58060800, 3686400, 29030400, 4300800, 406425600, 232243200
Offset: 0
Examples
The full triangle is 1; 1, 0; 1, 1/4, -1/4; 1, 17/36, -7/12, 1/9; 1, 181/288, -167/192, 77/288, -5/192; 1, 5197/7200, -613/576, 581/1440, -187/2880, 7/1800; 1, 4129/5400, -60239/51840, 5573/11520, -9877/103680, 1597/172800, -37/103680; ... Thus, for example, a degree 3 approximation is 1/Gamma(x+1) ~ 1 + 17/36x - 7/12x^2 + 1/9x^3. Therefore, T(3, 1) = 36, T(3, 2) = 12, etc.
Links
- Eric W. Weisstein, Newton's Forward Difference Formula, From MathWorld--A Wolfram Resource.
Crossrefs
Cf. A386675.
Programs
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Mathematica
T[n_, k_] := Denominator[Sum[(-1)^j * StirlingS1[j, k] * LaguerreL[j, 1] / j!,{j, 0, n}]] maxN = 10; Table[T[n, k], {n, 0, maxN}, {k, 0, n}]
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PARI
T(n, k) = denominator( sum(j=0, n, (-1)^j * stirling(j, k, 1) * pollaguerre(j,,1)/j!)); \\ Michel Marcus, Aug 02 2025
Formula
T(n, k) = denominator( Sum_{j=0..n} (-1)^j * Stirling1(j, k) * Lag(j, 1)/j! ) where Lag(n, x) is the Laguerre polynomial. Proof: Apply Newton's Forward Difference Formula to f(n) = 1/n!. Use the identity x * (x-1) * ... * (x - n + 1) = Sum_{k=0..n} Stirling1(n, k) * x^k and interchange the order of summation.
Comments