cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A386918 a(n) = 2^n * binomial(4*n,n).

Original entry on oeis.org

1, 8, 112, 1760, 29120, 496128, 8614144, 151557120, 2692684800, 48201359360, 868004380672, 15706806542336, 285362317180928, 5202031080243200, 95104728494899200, 1743063914667048960, 32016101348447354880, 589188508080622534656, 10861173739509105295360
Offset: 0

Views

Author

Seiichi Manyama, Aug 08 2025

Keywords

Crossrefs

Programs

  • Magma
    [2^n * Binomial(4*n,n): n in [0..26]]; // Vincenzo Librandi, Aug 11 2025
  • Mathematica
    Table[2^n*Binomial[4*n,n],{n,0,30}] (* Vincenzo Librandi, Aug 11 2025 *)
  • PARI
    a(n) = 2^n*binomial(4*n, n);
    

Formula

a(n) = Sum_{k=0..n} binomial(4*n,k) * binomial(4*n-k,n-k).
a(n) = [x^n] (1+x)^(4*n)/(1-x)^(3*n+1).
a(n) = [x^n] 1/(1-2*x)^(3*n+1).
a(n) = [x^n] (1+2*x)^(4*n).

A386920 a(n) = Sum_{k=0..n} binomial(4*n,k) * binomial(3*n-k,n-k).

Original entry on oeis.org

1, 7, 83, 1102, 15395, 221402, 3244430, 48173244, 722264355, 10910288290, 165788618138, 2531447611524, 38807906496398, 596945491933252, 9208704207465020, 142410375212008952, 2207122379129757987, 34272045530904650610, 533075544700619580002, 8304126391210396590900
Offset: 0

Views

Author

Seiichi Manyama, Aug 08 2025

Keywords

Crossrefs

Programs

  • Magma
    [&+[Binomial(4*n,k) * Binomial(3*n-k,n-k): k in [0..n]]: n in [0..25]]; // Vincenzo Librandi, Aug 10 2025
  • Mathematica
    Table[Sum[Binomial[4*n,k]*Binomial[3*n-k,n-k],{k,0,n}],{n,0,25}] (* Vincenzo Librandi, Aug 10 2025 *)
  • PARI
    a(n) = sum(k=0, n, binomial(4*n, k)*binomial(3*n-k, n-k));
    

Formula

a(n) = [x^n] (1+x)^(4*n)/(1-x)^(2*n+1).
a(n) = [x^n] 1/((1-x)^n * (1-2*x)^(2*n+1)).
a(n) = Sum_{k=0..n} 2^k * (-1)^(n-k) * binomial(4*n,k) * binomial(2*n-k-1,n-k).
a(n) = Sum_{k=0..n} 2^k * binomial(2*n+k,k) * binomial(2*n-k-1,n-k).
a(n) ~ (2 + sqrt(2)) * 2^(4*n-2) / sqrt(Pi*n). - Vaclav Kotesovec, Aug 21 2025
Showing 1-2 of 2 results.