cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A282293 Two-column array A(n, k) read by rows, where A(n, 1) and A(n, 2) respectively give values of q and p in the n-th double Wieferich prime pair, where p > q. Terms sorted first by increasing size of p, then by increasing size of q.

Original entry on oeis.org

2, 1093, 83, 4871, 2903, 18787, 911, 318917, 3, 1006003, 5, 1645333507
Offset: 1

Views

Author

Felix Fröhlich, Feb 11 2017

Keywords

Comments

Double Wieferich prime pairs are pairs of prime numbers p and q such that p^(q-1) == 1 (mod q^2) and q^(p-1) == 1 (mod p^2).
Pairs of primes p and q such that A274916(x, y) = 2, where x and y are the indices of p and q in A000040 respectively.
This sequence provides a "complete" listing of double Wieferich prime pairs. A124122 omits values of p where a smaller p with the same value of q in A124121 exists, while A266829 lists each value of p exactly once, regardless of how many values of q exist for that p.
There are two ways to retrieve the pair (p, q) from the data when looking at any specific value:
1. Look at the indices i of the terms. If the index is even, a(i) is the larger member p of a pair, so q is a(i-1). If the index is odd, a(i) is the smaller member q of the pair, so p is a(i+1).
2. Look at a term a(i) in the data section. If a(i-1) and a(i+1) are both larger than a(i), then a(i) is the smaller member of a pair and its partner is a(i+1). If a(i-1) and a(i+1) are both smaller than a(i), then a(i) is the larger member of a pair and its partner is a(i-1).
There are no further pairs with p*q <= 10^15 and p < 2^(1/3)*10^10 and only one additional Wieferich pair, namely (5, 188748146801), is known, but its position in the sequence is uncertain (cf. Logan, Mossinghoff, 2015).
Double Wieferich pairs were first mentioned by Inkeri, who showed that if Catalan's Diophantine equation x^p - y^q = 1 has a solution (x, y) for prime numbers p and q both congruent to 3 modulo 4, p > q and h(p) =/= 0 (mod q), where h(p) is the class number of the field k(sqrt(-p)), then (p, q) is a double Wieferich pair (cf. Inkeri, 1964, Theorem 2).
The pairs (2, 1093) and (83, 4871) were apparently first found by Aaltonen and Inkeri, who state that these two and a third one, (3, 1006003), from a table from Brillhart, Tonascia and Weinberger, are the only pairs they are aware of (cf. Aaltonen, Inkeri, 1991, Remark on p. 365).
The pairs (2903, 18787) and (911, 318917) were first found by Mignotte and Roy (cf. Keller, Richstein, 2005, p. 935) and later also by Ernvall and Metsänkylä in a search to 10^6, who also mention the pair (5, 1645333507) found by Montgomery (cf. Ernvall, Metsänkylä, 1997, p. 1360).
Several further conditions connecting double Wieferich pairs to Catalan's equation were obtained by Steiner, for example the result that if both p and q in a solution to the Catalan equation are congruent to 3 modulo 4 or both p and q satisfy either p == 3 (mod 4) and q == 5 (mod 8) or vice versa, then (p, q) is a double Wieferich pair (cf. Steiner, 1998, Theorems 7 and 8).
Mihailescu further showed that if the Catalan equation has a solution with p and q distinct odd primes and xy != 0, then q^2 | x, p^2 | y and p and q form a double Wieferich prime pair (cf. Mihailescu, 2003, Theorem 1).
If the Diophantine equation p^x - q^y = c has more than one solution with q an odd prime incongruent to 1 modulo 12, p < 2*q, gcd(p-1, q-1) even and (p, q, c) not one of (3, 2, 1), (2, 3, 5), (2, 3, 13), (2, 5, 3) or (13, 3, 10), then (p, q) is a double Wieferich pair (cf. Scott, Styer, 2004, pages 218-219).
Corollary to Proposition 4 in Pomerance, Selfridge, Wagstaff, 1980: Let p and q be primes and let c and d be composites such that c and d are base-p and base-q Fermat pseudoprimes, respectively. If p^2 divides d and q^2 divides c, then (p, q) is a double Wieferich pair.

Examples

			The primes 83 and 4871 satisfy 83^4870 == 1 (mod 23726641) and 4871^82 == 1 (mod 6889), respectively, so 83 and 4871 are terms of the sequence.
		

Crossrefs

Programs

  • PARI
    is_dwpp(n, k) = Mod(n, k^2)^(k-1)==1 && Mod(k, n^2)^(n-1)==1
    search(x, y) = forprime(p=x, y, forprime(q=1, p-1, if(is_dwpp(p, q), print1(q, ", ", p, ", "))))
    search(1, 1e6) \\ search pairs in the interval [1, 10^6]

A274916 Triangle T(n, k) read by rows: sum of residues p^(q-1) (mod q^2) and q^(p-1) (mod p^2), where p = prime(n) and q = prime(k) for k = 1, 2, ...., n-1.

Original entry on oeis.org

7, 17, 13, 18, 47, 44, 59, 5, 94, 38, 41, 112, 25, 133, 242, 223, 172, 226, 74, 188, 204, 61, 344, 250, 249, 128, 344, 317, 395, 399, 339, 306, 262, 347, 398, 412, 31, 440, 355, 835, 757, 737, 300, 713, 772, 190, 535, 301, 808, 137, 1013, 738, 647, 730, 1119
Offset: 1

Views

Author

Felix Fröhlich, Dec 11 2016

Keywords

Comments

T(n, k) = 2 iff (p, q) is a double Wieferich prime pair.

Examples

			For n = 652 and k = 23: prime(23) = 83 and prime(652) = 4871. 83 and 4871 form a double Wieferich prime pair, so 83^4870 (mod 4871^2) = 1 and 4871^82 (mod 83^2) = 1, hence T(652, 23) = 1+1 = 2.
Triangle starts
    7;
   17,  13;
   18,  47,  44;
   59,   5,  94,  38;
   41, 112,  25, 133, 242;
  223, 172, 226,  74, 188,  204;
   61, 344, 250, 249, 128,  344, 317;
  395, 399, 339, 306, 262,  347, 398, 412;
   31, 440, 355, 835, 757,  737, 300, 713, 772;
  190, 535, 301, 808, 137, 1013, 738, 647, 730, 1119;
		

Crossrefs

Programs

  • PARI
    t(n, k) = lift(Mod(prime(n), prime(k)^2)^(prime(k)-1)) + lift(Mod(prime(k), prime(n)^2)^(prime(n)-1))
    trianglerows(n) = for(x=2, n+1, for(y=1, x-1, print1(t(x, y), ", ")); print(""))
    trianglerows(6) \\ print upper 6 rows of triangle
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