cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A186511 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-4+5j^2. Complement of A186512.

Original entry on oeis.org

2, 3, 4, 6, 7, 8, 10, 11, 13, 14, 16, 17, 18, 20, 21, 23, 24, 26, 27, 28, 30, 31, 33, 34, 36, 37, 39, 40, 42, 43, 44, 46, 47, 49, 50, 52, 53, 55, 56, 57, 59, 60, 62, 63, 65, 66, 68, 69, 70, 72, 73, 75, 76, 78, 79, 81, 82, 83, 85, 86, 88, 89, 91, 92, 94, 95, 96, 98, 99, 101, 102, 104, 105, 107, 108, 110, 111, 112, 114, 115, 117, 118, 120, 121, 123, 124, 125, 127, 128, 130, 131, 133, 134, 136, 137, 138, 140, 141, 143, 144
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
The pairs (i,j) for which i^2=-4+5j^2 are (L(2h-1),F(2h-1)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
1........16........41........(-4+5j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 after -4+5j^2:
a=(2,3,4,6,7,8,10,11,13,14,16,...)=A186511
b=(1,5,9,12,15,19,22,25,29,32,...)=A186512.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking ui^2+vi+w and xj^2+yj+z *)
    d = -1/2; u = 1; v = 0; w = 0; x = 5; y = 0; z =-4;
    h[n_] := -y + (4 x (u*n^2 + v*n + w - z - d) + y^2)^(1/2);
    a[n_] := n + Floor[h[n]/(2 x)];
    k[n_] := -v + (4 u (x*n^2 + y*n + z - w + d) + v^2)^(1/2);
    b[n_] := n + Floor[k[n]/(2 u)];
    Table[a[n], {n, 1, 100}]  (* A186511 *)
    Table[b[n], {n, 1, 100}]  (* A186512 *)

Formula

a(n)=n+floor(sqrt((n^2)/5+9/10))=A186511(n).
b(n)=n+floor(sqrt(5n^2-9/2))=A186512(n).

A186512 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-4+5j^2. Complement of A186511.

Original entry on oeis.org

1, 5, 9, 12, 15, 19, 22, 25, 29, 32, 35, 38, 41, 45, 48, 51, 54, 58, 61, 64, 67, 71, 74, 77, 80, 84, 87, 90, 93, 97, 100, 103, 106, 109, 113, 116, 119, 122, 126, 129, 132, 135, 139, 142, 145, 148, 152, 155, 158, 161, 165, 168, 171, 174, 177, 181, 184, 187, 190, 194, 197, 200, 203, 207, 210, 213, 216, 220, 223, 226, 229, 232, 236, 239, 242, 245, 249, 252, 255, 258, 262, 265
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
The pairs (i,j) for which i^2=-4+5j^2 are (L(2h-1),F(2h-1)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
1........16........41........(-4+5j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 after -4+5j^2:
a=(2,3,4,6,7,8,10,11,13,14,16,...)=A186511
b=(1,5,9,12,15,19,22,25,29,32,...)=A186512.
		

Crossrefs

Programs

Formula

a(n)=n+floor(sqrt((n^2)/5+9/10))=A186511(n).
b(n)=n+floor(sqrt(5n^2-9/2))=A186512(n).

A186513 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=4+5j^2. Complement of A186514.

Original entry on oeis.org

1, 2, 3, 5, 7, 8, 9, 11, 12, 14, 15, 17, 18, 20, 21, 23, 24, 25, 27, 28, 30, 31, 33, 34, 36, 37, 39, 40, 41, 43, 44, 46, 47, 49, 50, 52, 53, 54, 56, 57, 59, 60, 62, 63, 65, 66, 67, 69, 70, 72, 73, 75, 76, 78, 79, 81, 82, 83, 85, 86, 88, 89, 91, 92, 94, 95, 96, 98, 99, 101, 102, 104, 105, 107, 108, 109, 111, 112, 114, 115, 117, 118, 120, 121, 123, 124, 125, 127, 128, 130, 131, 133, 134, 136, 137, 138, 140, 141, 143, 144
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
The pairs (i,j) for which i^2=4+5j^2 are (L(2h),F(2h)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
......9.....24.......49.. (4+5j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 before 4+5j^2:
a=(1,2,3,5,7,8,9,11,12,14,15,17,..)=A186513
b=(4,6,10,13,16,19,22,26,29,32,...)=A186514.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking ui^2+vi+w and xj^2+yj+z *)
    d = 1/2; u = 1; v = 0; w = 0; x = 5; y = 0; z = 4;
    h[n_] := -y + (4 x (u*n^2 + v*n + w - z - d) + y^2)^(1/2);
    a[n_] := n + Floor[h[n]/(2 x)];
    k[n_] := -v + (4 u (x*n^2 + y*n + z - w + d) + v^2)^(1/2);
    b[n_] := n + Floor[k[n]/(2 u)];
    Table[a[n], {n, 1, 100}]  (* A186513 *)
    Table[b[n], {n, 1, 100}]  (* A186514 *)

Formula

a(n)=n+floor(sqrt((n^2)/5-9/10))=A186513(n).
b(n)=n+floor(sqrt(5n^2+9/2))=A186514(n).

A186514 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=4+5j^2. Complement of A186513.

Original entry on oeis.org

4, 6, 10, 13, 16, 19, 22, 26, 29, 32, 35, 38, 42, 45, 48, 51, 55, 58, 61, 64, 68, 71, 74, 77, 80, 84, 87, 90, 93, 97, 100, 103, 106, 110, 113, 116, 119, 122, 126, 129, 132, 135, 139, 142, 145, 148, 152, 155, 158, 161, 165, 168, 171, 174, 178, 181, 184, 187, 190, 194, 197, 200, 203, 207, 210, 213, 216, 220, 223, 226, 229, 233, 236, 239, 242, 245, 249, 252, 255, 258, 262, 265
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
The pairs (i,j) for which i^2=4+5j^2 are (L(2h),F(2h)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
......9.....24.......49.. (4+5j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 before 4+5j^2:
a=(1,2,3,5,7,8,9,11,12,14,15,17,..)=A186513
b=(4,6,10,13,16,19,22,26,29,32,...)=A186514.
		

Crossrefs

Programs

Formula

a(n)=n+floor((1/10)(-4+sqrt(20n^2+6)))=A186513(n).
b(n)=n+floor(sqrt(5n^2+4n+1/2))=A186514(n).

A186515 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=4+5j^2. Complement of A186516.

Original entry on oeis.org

1, 2, 4, 5, 7, 8, 10, 11, 12, 14, 15, 17, 18, 20, 21, 23, 24, 26, 27, 28, 30, 31, 33, 34, 36, 37, 39, 40, 41, 43, 44, 46, 47, 49, 50, 52, 53, 54, 56, 57, 59, 60, 62, 63, 65, 66, 68, 69, 70, 72, 73, 75, 76, 78, 79, 81, 82, 83, 85, 86, 88, 89, 91, 92, 94, 95, 96, 98, 99, 101, 102, 104, 105, 107, 108, 109, 111, 112, 114, 115, 117, 118, 120, 121, 123, 124, 125, 127, 128, 130, 131, 133, 134, 136, 137, 138, 140, 141, 143, 144
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
The pairs (i,j) for which i^2=4+5j^2 are (L(2h),F(2h)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
......9.....24.......49.. (4+5j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 after 4+5j^2:
a=(1,2,4,5,7,8,10,11,12,14,15,17,..)=A186515
b=(3,6,9,13,16,19,22,25,29,32,35,..)=A186516.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking ui^2+vi+w and xj^2+yj+z *)
    d = -1/2; u = 1; v = 0; w = 0; x = 5; y = 0; z = 4;
    h[n_] := -y + (4 x (u*n^2 + v*n + w - z - d) + y^2)^(1/2);
    a[n_] := n + Floor[h[n]/(2 x)];
    k[n_] := -v + (4 u (x*n^2 + y*n + z - w + d) + v^2)^(1/2);
    b[n_] := n + Floor[k[n]/(2 u)];
    Table[a[n], {n, 1, 100}]  (* A186515 *)
    Table[b[n], {n, 1, 100}]  (* A186516 *)

Formula

a(n)=n+floor(sqrt((n^2)/5-7/10))=A186515(n).
b(n)=n+floor(sqrt(5n^2+7/2))=A186516(n).

A186516 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=4+5j^2. Complement of A186515.

Original entry on oeis.org

3, 6, 9, 13, 16, 19, 22, 25, 29, 32, 35, 38, 42, 45, 48, 51, 55, 58, 61, 64, 67, 71, 74, 77, 80, 84, 87, 90, 93, 97, 100, 103, 106, 110, 113, 116, 119, 122, 126, 129, 132, 135, 139, 142, 145, 148, 152, 155, 158, 161, 165, 168, 171, 174, 177, 181, 184, 187, 190, 194, 197, 200, 203, 207, 210, 213, 216, 220, 223, 226, 229, 233, 236, 239, 242, 245, 249, 252, 255, 258, 262, 265, 268, 271
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
The pairs (i,j) for which i^2=4+5j^2 are (L(2h),F(2h)), where L=A000032 (Lucas numbers) and F=A000045 (Fibonacci numbers).

Examples

			First, write
1..4..9..16..25..36..49.. (i^2)
......9.....24.......49.. (4+5j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 after 4+5j^2:
a=(1,2,4,5,7,8,10,11,12,14,15,17,..)=A186515
b=(3,6,9,13,16,19,22,25,29,32,35,..)=A186516.
		

Crossrefs

Programs

Formula

a(n)=n+floor(sqrt((n^2)/5-7/10))=A186515(n).
b(n)=n+floor(sqrt(5n^2+7/2))=A186516(n).

A186539 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-2+3j^2. Complement of A186540.

Original entry on oeis.org

1, 3, 4, 6, 7, 9, 11, 12, 14, 15, 17, 18, 20, 22, 23, 25, 26, 28, 29, 31, 33, 34, 36, 37, 39, 41, 42, 44, 45, 47, 48, 50, 52, 53, 55, 56, 58, 59, 61, 63, 64, 66, 67, 69, 70, 72, 74, 75, 77, 78, 80, 82, 83, 85, 86, 88, 89, 91, 93, 94, 96, 97, 99, 100, 102, 104, 105, 107, 108, 110, 111, 113, 115, 116, 118, 119, 121, 123, 124, 126, 127, 129, 130, 132, 134, 135, 137, 138, 140, 141, 143, 145, 146, 148, 149, 151, 153, 154, 156, 157
Offset: 1

Views

Author

Clark Kimberling, Feb 23 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.
Differs from A059555 at n=97, 123, 194, 220, 246, ... - R. J. Mathar, May 18 2020

Examples

			First, write
1..4..9..16..25..36..49.... (i^2)
.......10....25.....46.. (-2+3j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 before -2+3j^2:
a=(1,3,4,6,7,9,11,12,14,15,17,18,..)=A186539
b=(2,5,8,10,13,16,19,21,24,27,30...)=A186540.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking ui^2+vi+w and xj^2+yj+z *)
    d = 1/2; u = 1; v = 0; w = 0; x = 3; y = 0; z = -2;
    h[n_] := -y + (4 x (u*n^2 + v*n + w - z - d) + y^2)^(1/2);
    a[n_] := n + Floor[h[n]/(2 x)];
    k[n_] := -v + (4 u (x*n^2 + y*n + z - w + d) + v^2)^(1/2);
    b[n_] := n + Floor[k[n]/(2 u)];
    Table[a[n], {n, 1, 100}]  (* A186539 *)
    Table[b[n], {n, 1, 100}]  (* A186540 *)

Formula

a(n)=n+floor(sqrt((1/3)n^2+1/24))=A186539(n).
b(n)=n+floor(sqrt(3n^2-3/2))=A186540(n).

A186541 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-2+3j^2. Complement of A186542.

Original entry on oeis.org

2, 3, 4, 6, 8, 9, 11, 12, 14, 15, 17, 18, 20, 22, 23, 25, 26, 28, 30, 31, 33, 34, 36, 37, 39, 41, 42, 44, 45, 47, 48, 50, 52, 53, 55, 56, 58, 59, 61, 63, 64, 66, 67, 69, 70, 72, 74, 75, 77, 78, 80, 82, 83, 85, 86, 88, 89, 91, 93, 94, 96, 97, 99, 100, 102, 104, 105, 107, 108, 110, 112, 113, 115, 116, 118, 119, 121, 123, 124, 126, 127, 129, 130, 132, 134, 135, 137, 138, 140, 141, 143, 145, 146, 148, 149, 151, 153, 154, 156, 157
Offset: 1

Views

Author

Clark Kimberling, Feb 23 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
.........10.....25.....46.. (-2+3j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 after -2+3j^2:
a=(2,3,4,6,8,9,11,12,14,15,17,18,..)=A186541
b=(1,5,7,10,13,16,19,21,24,27,29...)=A186542.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking ui^2+vi+w and xj^2+yj+z *)
    d = -1/2; u = 1; v = 0; w = 0; x = 3; y = 0; z = -2;
    h[n_] := -y + (4 x (u*n^2 + v*n + w - z - d) + y^2)^(1/2);
    a[n_] := n + Floor[h[n]/(2 x)];
    k[n_] := -v + (4 u (x*n^2 + y*n + z - w + d) + v^2)^(1/2);
    b[n_] := n + Floor[k[n]/(2 u)];
    Table[a[n], {n, 1, 100}]  (* A186539 *)
    Table[b[n], {n, 1, 100}]  (* A186540 *)

Formula

a(n)=n+floor(sqrt((1/3)n^2+5/6))=A186541(n).
b(n)=n+floor(sqrt(3n^2-5/2))=A186542(n).

A186542 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=i^2 and g(j)=-2+3j^2. Complement of A186541.

Original entry on oeis.org

1, 5, 7, 10, 13, 16, 19, 21, 24, 27, 29, 32, 35, 38, 40, 43, 46, 49, 51, 54, 57, 60, 62, 65, 68, 71, 73, 76, 79, 81, 84, 87, 90, 92, 95, 98, 101, 103, 106, 109, 111, 114, 117, 120, 122, 125, 128, 131, 133, 136, 139, 142, 144, 147, 150, 152, 155, 158, 161, 163, 166, 169, 172, 174, 177, 180, 183, 185, 188, 191, 193, 196, 199, 202, 204, 207, 210, 213, 215, 218, 221, 224, 226, 229, 232, 234, 237, 240
Offset: 1

Views

Author

Clark Kimberling, Feb 23 2011

Keywords

Comments

See A186219 for a discussion of adjusted joint rank sequences.

Examples

			First, write
1..4..9..16..25..36..49..... (i^2)
.........10.....25.....46.. (-2+3j^2)
Then replace each number by its rank, where ties are settled by ranking i^2 after -2+3j^2:
a=(2,3,4,6,8,9,11,12,14,15,17,18,..)=A186541
b=(1,5,7,10,13,16,19,21,24,27,29...)=A186542.
		

Crossrefs

Programs

Formula

a(n)=n+floor(sqrt((1/3)n^2+5/6))=A186541(n).
b(n)=n+floor(sqrt(3n^2-5/2))=A186542(n).

A186228 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f and g are the triangular numbers and heptagonal numbers. Complement of A186227.

Original entry on oeis.org

2, 5, 8, 11, 15, 18, 21, 24, 27, 31, 34, 37, 40, 44, 47, 50, 53, 57, 60, 63, 66, 70, 73, 76, 79, 82, 86, 89, 92, 95, 99, 102, 105, 108, 112, 115, 118, 121, 125, 128, 131, 134, 137, 141, 144, 147, 150, 154, 157, 160, 163, 167, 170, 173, 176, 180, 183, 186, 189, 192, 196, 199, 202, 205, 209, 212, 215, 218, 222, 225, 228, 231, 235, 238, 241, 244, 248, 251, 254, 257, 260, 264, 267, 270, 273, 277, 280, 283, 286, 290, 293, 296, 299, 303, 306, 309
Offset: 1

Views

Author

Clark Kimberling, Feb 16 2011

Keywords

Comments

See A186227.

Examples

			See A186227.
		

Crossrefs

Programs

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