cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 11-18 of 18 results.

A262526 Any number greater than a(n) can conjecturally be represented in more ways by sums of three base-10 palindromes than a(n).

Original entry on oeis.org

1, 2, 3, 4, 98, 120, 142, 164, 172, 192, 212, 223, 2082, 2102, 2203, 2213, 130282, 130992, 131392, 131492, 131592, 131742, 131752, 131792, 131902, 132002, 132102, 132192, 132202, 132482, 132502, 132602, 132662, 132672, 132752, 132782, 132802
Offset: 1

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Author

Hugo Pfoertner, Sep 25 2015

Keywords

Comments

The corresponding representation counts are provided in A262527. Positions of latest occurrence of increasing minima of representation counts in A261132. The sequence provides numerical evidence for the validity of the conjecture that every number is the sum of three palindromes.

Examples

			a(5)=98 because A261132(k)>5 for all k>98.
a(7)=142 because A261132(k)>A262527(7)=8 for all k>142.
		

Crossrefs

See A261422, A262544, A262545 for another approach.

A262527 Conjectured minimum number of ways to represent a number >= A262526(i) by sums of three base-10 palindromes.

Original entry on oeis.org

1, 2, 3, 4, 5, 6, 8, 11, 13, 14, 15, 16, 17, 18, 21, 27, 29, 35, 41, 45, 48, 51, 54, 55, 56, 61, 63, 64, 65, 74, 75, 79, 80, 82, 83, 85, 86, 87, 91, 111, 112, 113, 114, 115, 116, 118, 120, 121, 124, 127, 133, 134, 138, 140, 141, 142, 145, 147, 150, 153, 165, 169, 171, 174, 175, 177, 179, 180, 183, 184, 185
Offset: 1

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Author

Hugo Pfoertner, Sep 25 2015

Keywords

Comments

The sequence is obtained by sorting the counts A261132 into increasing order together with their positions of occurrence. If a new record in the sorted A261132 is found, the index of its latest occurrence in A261132 becomes the next term in A262526 and the corresponding value of A261132 becomes a(n).
7 is not in the sequence, because the latest occurrence of 7 is at A261132(64), whereas the latest occurrence of 6 had already set the record to A262526(6) = 120.
a(7) = 8 corresponds to the latest occurrence of 8 at A261132(142), thus A262526(7) = 142.

Examples

			a(5) = 5 because A261132(k) > 5 for all k > A262526(5) = 98.
		

Crossrefs

See A261422, A262544, A262545 for another approach.

A109326 Smallest positive number that requires n steps to be represented as a sum of palindromes using the greedy algorithm.

Original entry on oeis.org

1, 10, 21, 1022, 101023, 1000101024
Offset: 1

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Author

David Wasserman, Aug 11 2005

Keywords

Comments

Index of first occurrence of n in A088601.
Presumably this sequence is unbounded. - N. J. A. Sloane, Aug 28 2015
The greedy algorithm means iteration of A261424 until a palindrome is reached. For n = 3, 4, ... we have a(n+1) = 10^L(n) + a(n) + 1 with L(n) = 2^(n-2) + 1 = length(a(n))*2 - 3 for n > 3. We have a(7) <= 10^17 + 1000101025, a(8) <= 10^33 + 10^17 + 1000101026, a(9) <= 10^65 + 10^33 + 10^17 + 1000101027, a(10) <= 10^129 + 10^65 + 10^33 + 10^17 + 1000101028, etc, with conjectured equality. - M. F. Hasler, Sep 08 2015, edited Sep 09 2018

Crossrefs

Programs

  • Python
    # uses functions in A088601
    def afind(limit):
        record = 0
        for i in range(1, limit+1):
            steps = A088601(i)
            if steps > record: print(i, end=", "); record = steps
    afind(10**6) # Michael S. Branicky, Jul 12 2021

Formula

a(n) = Sum_{0 <= k <= n-3} 10^(2^k+1) + n - 82, for n > 2 (conjectured). - M. F. Hasler, Sep 08 2015

Extensions

Edited by N. J. A. Sloane, Aug 28 2015

A261680 Number of ordered quadruples (u,v,w,x) of binary palindromes (see A006995) with u+v+w+x=n.

Original entry on oeis.org

1, 4, 6, 8, 13, 16, 22, 28, 34, 44, 50, 60, 59, 72, 70, 80, 92, 88, 114, 96, 125, 104, 152, 120, 172, 144, 188, 152, 215, 144, 242, 160, 272, 172, 302, 180, 329, 216, 352, 240, 388, 228, 430, 228, 442, 212, 476, 192, 506, 228, 496, 248, 540, 252, 582, 276, 592
Offset: 0

Views

Author

N. J. A. Sloane, Sep 04 2015

Keywords

Comments

Conjecture: a(n)>0: every number is the sum of four binary palindromes. (Compare A261422, A261675.)

Crossrefs

Formula

G.f. = (Sum_{p in A006995} x^p)^4.

A282584 Number of compositions (ordered partitions) of n into decimal palindromes (A002113).

Original entry on oeis.org

1, 1, 2, 4, 8, 16, 32, 64, 128, 256, 511, 1022, 2042, 4081, 8156, 16300, 32576, 65104, 130112, 260032, 519681, 1038595, 2075660, 4148259, 8290402, 16568581, 33112734, 66176648, 132255728, 264316464, 528243231, 1055707644, 2109858797, 4216606912, 8426997041, 16841569684, 33658308890, 67266993433
Offset: 0

Views

Author

Ilya Gutkovskiy, Feb 19 2017

Keywords

Examples

			a(4) = 8 because we have [4], [3, 1], [2, 2], [2, 1, 1], [1, 3], [1, 2, 1], [1, 1, 2] and [1, 1, 1, 1].
		

Crossrefs

Programs

  • Mathematica
    nmax = 37; CoefficientList[Series[1/(1 - Sum[Boole[PalindromeQ[k]] x^k, {k, 1, nmax}]), {x, 0, nmax}], x]

Formula

G.f.: 1/(1 - Sum_{k>=2} x^A002113(k)).

A282585 Number of ways to write n as an ordered sum of 3 squarefree palindromes (A071251).

Original entry on oeis.org

0, 0, 0, 1, 3, 6, 7, 9, 12, 19, 21, 21, 18, 24, 27, 28, 18, 18, 19, 24, 15, 10, 6, 12, 12, 12, 9, 9, 12, 15, 18, 12, 9, 7, 15, 15, 15, 9, 12, 15, 18, 18, 12, 9, 9, 18, 15, 12, 0, 9, 9, 9, 0, 0, 0, 6, 6, 9, 12, 9, 12, 15, 18, 18, 12, 9, 13, 18, 18, 18, 9, 15, 18, 21, 18, 12, 9, 15, 21, 21, 21, 9, 18, 21, 24, 18
Offset: 0

Views

Author

Ilya Gutkovskiy, Feb 19 2017

Keywords

Comments

Every number can be written as the sum of 3 palindromes (see A261132 and A261422).
Conjecture: a(n) > 0 for any sufficiently large n.
Additional conjecture: every number > 3 can be written as the sum of 4 squarefree palindromes.

Examples

			a(22) = 6 because we have [11, 6, 5], [11, 5, 6] [6, 11, 5], [6, 5, 11], [5, 11, 6] and [5, 6, 11].
		

Crossrefs

Programs

  • Mathematica
    nmax = 85; CoefficientList[Series[Sum[Boole[SquareFreeQ[k] && PalindromeQ[k]] x^k, {k, 1, nmax}]^3, {x, 0, nmax}], x]

Formula

G.f.: (Sum_{k>=1} x^A071251(k))^3.

A261916 Smallest p such that n can be written as n = p+q+r where p>=q>=r>=0 are palindromes.

Original entry on oeis.org

0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9, 9, 9, 11, 11, 11, 11, 22, 11, 22, 22, 22, 22, 22, 22, 22, 22, 22, 33, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 44, 22, 33, 33, 33, 33, 33, 33, 33, 33, 33, 55, 22, 33, 33, 33, 33, 33
Offset: 0

Views

Author

N. J. A. Sloane, Sep 11 2015

Keywords

Comments

Every number is the sum of three palindromes.

Examples

			Initial values of n,p,q,r are:
0 0 0 0
1 1 0 0
2 1 1 0
3 1 1 1
4 2 1 1
5 2 2 1
6 2 2 2
7 3 3 1
...
25 9 9 7
26 9 9 8
27 9 9 9
28 11 11 6
29 11 11 7
30 11 11 8
...
33 11 11 11
34 22 11 1
...
		

Crossrefs

If "smallest" is changed to "largest" we get a sequence which agrees with the palindromic floor function A261423 for at least 300 terms.

Extensions

Edited by Alois P. Heinz, Dec 29 2018

A282845 Number of ways to write n as an ordered sum of 6 prime power palindromes (A084092).

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 1, 6, 21, 56, 126, 246, 432, 702, 1077, 1576, 2232, 3072, 4112, 5352, 6801, 8422, 10197, 12102, 14117, 16146, 18177, 20112, 21882, 23382, 24661, 25566, 26136, 26316, 26181, 25560, 24677, 23436, 21981, 20226, 18486, 16536, 14642, 12702, 10962, 9166, 7662, 6222, 5042, 3912, 3096, 2306, 1746, 1236, 921, 600
Offset: 0

Views

Author

Ilya Gutkovskiy, Feb 22 2017

Keywords

Comments

Is there k which satisfies a(n) > 0 for all n > k?

Examples

			a(7) = 6 because we have:
[2, 1, 1, 1, 1, 1]
[1, 2, 1, 1, 1, 1]
[1, 1, 2, 1, 1, 1]
[1, 1, 1, 2, 1, 1]
[1, 1, 1, 1, 2, 1]
[1, 1, 1, 1, 1, 2]
		

Crossrefs

Programs

  • Mathematica
    nmax = 55; CoefficientList[Series[(x + Sum[Boole[PrimePowerQ[k] && PalindromeQ[k]] x^k, {k, 1, nmax}])^6, {x, 0, nmax}], x]

Formula

G.f.: (Sum_{k>=1} x^A084092(k))^6.
Previous Showing 11-18 of 18 results.