cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A151910 First differences of A001682.

Original entry on oeis.org

21, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23, 21, 23, 21, 23, 21, 21, 23
Offset: 1

Views

Author

Harvey P. Dale, Aug 08 2009

Keywords

Comments

a(n) = A001682(n+1) - A001682(n).

Programs

  • Haskell
    a151910 n = a151910_list !! (n-1)
    a151910_list = zipWith (-) (tail a001682_list) a001682_list
    -- Reinhard Zumkeller, Oct 10 2011

Extensions

Offset corrected and initial term added by Reinhard Zumkeller, Oct 10 2011

A115566 Numbers k such that 2^k, 2^(k+1) and 2^(k+2) have the same number of digits.

Original entry on oeis.org

1, 4, 7, 10, 11, 14, 17, 20, 21, 24, 27, 30, 31, 34, 37, 40, 41, 44, 47, 50, 51, 54, 57, 60, 61, 64, 67, 70, 71, 74, 77, 80, 81, 84, 87, 90, 91, 94, 97, 100, 103, 104, 107, 110, 113, 114, 117, 120, 123, 124, 127, 130, 133, 134, 137, 140, 143, 144, 147, 150, 153, 154
Offset: 1

Views

Author

Stefan Steinerberger, Mar 11 2006

Keywords

Comments

The density of this sequence is 1 - 2*log_10(2) = 0.3979400086720376...

Examples

			2^4 = 16, 2^5 = 32, 2^6 = 64: all these numbers have two digits.
2^10 = 1024, 2^11 = 2048, 2^12 = 4096: all these numbers have three digits.
		

Crossrefs

Cf. A001682 (same definition with 3 instead of 2).
Cf. A034887 (number of digits in 2^n).

Programs

  • Magma
    [k:k in [1..160]|#Intseq(2^k) eq #Intseq(2^(k+2))]; // Marius A. Burtea, May 20 2019
  • Maple
    select(n -> ilog10(2^n)=ilog10(2^(n+2)), [$1..1000]); # Robert Israel, May 19 2019
  • Mathematica
    Select[Range[220], Floor[Log[10, 2]*# ] == Floor[Log[10, 2]*(# + 2)] &]

Formula

floor(log_10(2)*k) = floor(log_10(2)*(k+1)) = floor(log_10(2)*(k+2)).
Showing 1-2 of 2 results.