cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A001864 Total height of rooted trees with n labeled nodes.

Original entry on oeis.org

0, 2, 24, 312, 4720, 82800, 1662024, 37665152, 952401888, 26602156800, 813815035000, 27069937855488, 972940216546896, 37581134047987712, 1552687346633913000, 68331503866677657600, 3191386068123595166656, 157663539876436721860608
Offset: 1

Views

Author

Keywords

Comments

a(n) is the total number of nonrecurrent elements mapped into a recurrent element in all functions f:{1,2,...,n}->{1,2,...,n}. a(n) = Sum_{k=1..n-1} A216971(n,k)*k. - Geoffrey Critzer, Jan 01 2013
a(n) is the sum of the lengths of all cycles over all functions f:{1,2,...,n}->{1,2,...,n}. Fixed points are taken to have length zero. a(n) = Sum_{k=2..n} A066324(n,k)*(k-1). - Geoffrey Critzer, Aug 19 2013

References

  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Programs

  • Maple
    A001864 := proc(n) local k; add(n!*n^k/k!, k=0..n-2); end;
  • Mathematica
    Table[Sum[Binomial[n,k](n-k)^(n-k) k^k,{k,1,n-1}],{n,20}] (* Harvey P. Dale, Oct 10 2011 *)
    a[n_] := n*(n-1)*Exp[n]*Gamma[n-1, n] // Round; Table[a[n], {n, 1, 18}]  (* Jean-François Alcover, Jun 24 2013 *)
  • PARI
    a(n)=sum(k=1,n-1,binomial(n,k)*(n-k)^(n-k)*k^k)
    
  • Python
    from math import comb
    def A001864(n): return (sum(comb(n,k)*(n-k)**(n-k)*k**k for k in range(1,(n+1>>1)))<<1) + (0 if n&1 else comb(n,m:=n>>1)*m**n) # Chai Wah Wu, Apr 25-26 2023

Formula

a(n) = n*A000435(n).
E.g.f: (LambertW(-x)/(1+LambertW(-x)))^2. - Vladeta Jovovic, Apr 10 2001
a(n) = Sum_{k=1..n-1} binomial(n, k)*(n-k)^(n-k)*k^k. - Benoit Cloitre, Mar 22 2003
a(n) ~ sqrt(Pi/2)*n^(n+1/2). - Vaclav Kotesovec, Aug 07 2013
a(n) = n! * Sum_{k=0..n-2} n^k/k!. - Jianing Song, Aug 08 2022