A047354 Numbers that are congruent to {0, 1, 2} mod 7.
0, 1, 2, 7, 8, 9, 14, 15, 16, 21, 22, 23, 28, 29, 30, 35, 36, 37, 42, 43, 44, 49, 50, 51, 56, 57, 58, 63, 64, 65, 70, 71, 72, 77, 78, 79, 84, 85, 86, 91, 92, 93, 98, 99, 100, 105, 106, 107, 112, 113, 114, 119, 120, 121, 126, 127, 128, 133, 134, 135, 140, 141
Offset: 1
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..3000
- Index entries for linear recurrences with constant coefficients, signature (1, 0, 1, -1).
Programs
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Magma
[n : n in [0..150] | n mod 7 in [0..2]]; // Wesley Ivan Hurt, Jun 08 2016
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Maple
seq(7*floor(n/3)+(n mod 3), n=0..60); # Gary Detlefs, Mar 09 2010
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Mathematica
Flatten[{#,#+1,#+2}&/@(7Range[0,20])] (* Harvey P. Dale, Mar 05 2011 *)
Formula
a(n) = 7*floor(n/3)+(n mod 3), with offset 0 and a(0)=0. - Gary Detlefs, Mar 09 2010
From R. J. Mathar, Mar 29 2010: (Start)
G.f.: x^2*(1+x+5*x^2)/((1+x+x^2) * (x-1)^2).
a(n) = a(n-1) + a(n-3) - a(n-4) for n>4. (End)
a(n+1) = Sum_{k>=0} A030341(n,k)*b(k) with b(0)=1 and b(k)=7*3^(k-1) for k>0. - Philippe Deléham, Oct 24 2011
From Wesley Ivan Hurt, Jun 08 2016: (Start)
a(n) = (21*n-33-12*cos(2*n*Pi/3)+4*sqrt(3)*sin(2*n*Pi/3))/9.
a(3k) = 7k-5, a(3k-1) = 7k-6, a(3k-2) = 7k-7. (End)
a(n) = n + 4*floor((n-1)/3) - 1. - Bruno Berselli, Feb 06 2017