cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A066180 a(n) = smallest base b so that repunit (b^prime(n) - 1) / (b - 1) is prime, where prime(n) = n-th prime; or 0 if no such base exists.

Original entry on oeis.org

2, 2, 2, 2, 5, 2, 2, 2, 10, 6, 2, 61, 14, 15, 5, 24, 19, 2, 46, 3, 11, 22, 41, 2, 12, 22, 3, 2, 12, 86, 2, 7, 13, 11, 5, 29, 56, 30, 44, 60, 304, 5, 74, 118, 33, 156, 46, 183, 72, 606, 602, 223, 115, 37, 52, 104, 41, 6, 338, 217, 13, 136, 220, 162, 35, 10, 218, 19, 26, 39
Offset: 1

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Author

Frank Ellermann, Dec 15 2001

Keywords

Comments

Is a(n) = 0 possible?
Let p be the n-th prime; Cp(x) be the p-th cyclotomic polynomial (x^p - 1)/(x - 1); a(n) is the least k > 1 such that Cp(k) is prime.
The values associated with a(5) and a(8) through a(70) have been certified prime with Primo. (a(1) through a(4), a(6) and a(7) give prime(2), prime(4), prime(11), prime(31), prime(1028) and prime(12251), respectively.)

Examples

			a(5) = 5 because 11 is the 5th prime; (b^5 - 1)/(b - 1) is composite for b = 2,3,4 and prime ((5^11 - 1)/4 = 12207031) for b = 5.
b = 61 for prime(12) = 37 because (61^37 - 1)/60 is prime and 61 is the least base b that makes (b^37 - 1)/(b - 1) a prime.
		

References

  • Paulo Ribenboim, "The New Book of Prime Numbers Records", Springer, 1996, p. 353.

Crossrefs

Cf. A004023 (prime repunits in base 10), A000043 (prime repunits in base 2, Mersenne primes), A055129 (table of repunits).

Programs

  • Mathematica
    Table[p = Prime[n]; b = 1; While[b++; ! PrimeQ[(b^p - 1)/(b - 1)]]; b, {n, 1, 70}] (* Lei Zhou, Oct 07 2011 *)
  • PARI
    /* This program assumes (probable) primes exist for each n. */
    /* All 70 (probable) primes found by this program have been proved prime. */
    gen_repunit(b,n) = (b^prime(n)-1)/(b-1);
    for(n=1,70, b=1; until(isprime(p), b++; p=gen_repunit(b,n)); print1(b,","));

Formula

a(n) = A085398(prime(n)).

Extensions

Sequence extended to 16 terms by Don Reble, Dec 18 2001
More terms from Rick L. Shepherd, Sep 14 2002
Entry revised by N. J. A. Sloane, Jul 23 2006

A128164 Least k > 2 such that (n^k - 1)/(n-1) is prime, or 0 if no such prime exists.

Original entry on oeis.org

3, 3, 0, 3, 3, 5, 3, 0, 19, 17, 3, 5, 3, 3, 0, 3, 25667, 19, 3, 3, 5, 5, 3, 0, 7, 3, 5, 5, 5, 7, 0, 3, 13, 313, 0, 13, 3, 349, 5, 3, 1319, 5, 5, 19, 7, 127, 19, 0, 3, 4229, 103, 11, 3, 17, 7, 3, 41, 3, 7, 7, 3, 5, 0, 19, 3, 19, 5, 3, 29, 3, 7, 5, 5, 3, 41, 3, 3, 5, 3, 0, 23, 5, 17, 5, 11, 7, 61, 3, 3
Offset: 2

Views

Author

Alexander Adamchuk, Feb 20 2007

Keywords

Comments

a(n) = A084740(n) for all n except n = p-1, where p is an odd prime, for which A084740(n) = 2.
All nonzero terms are odd primes.
a(n) = 0 for n = {4,9,16,25,32,36,49,64,81,100,121,125,144,...}, which are the perfect powers with exceptions of the form n^(p^m) where p>2 and (n^(p^(m+1))-1)/(n^(p^m)-1) are prime and m>=1 (in which case a(n^(p^m))=p). - Max Alekseyev, Jan 24 2009
a(n) = 3 for n in A002384, i.e., for n such that n^2 + n + 1 is prime.
a(152) > 20000. - Eric Chen, Jun 01 2015
a(n) is the least number k such that (n^k - 1)/(n-1) is a Brazilian prime, or 0 if no such Brazilian prime exists. - Bernard Schott, Apr 23 2017
These corresponding Brazilian primes are in A285642. - Bernard Schott, Aug 10 2017
a(152) = 270217, see the top PRP link. - Eric Chen, Jun 04 2018
a(184) = 16703, a(200) = 17807, a(210) = 19819, a(306) = 26407, a(311) = 36497, a(326) = 26713, a(331) = 25033; a(185) > 66337, a(269) > 63659, a(281) > 63421, and there are 48 unknown a(n) for n <= 1024. - Eric Chen, Jun 04 2018
Six more terms found: a(522)=20183, a(570)=12907, a(684)=22573, a(731)=15427, a(820)=12043, a(996)=14629. - Michael Stocker, Apr 09 2020

Examples

			a(7) = 5 because (7^5 - 1)/6 = 2801 = 11111_7 is prime and (7^k - 1)/6 = 1, 8, 57, 400 for k = 1, 2, 3, 4. - _Bernard Schott_, Apr 23 2017
		

Crossrefs

Cf. A002384, A049409, A100330, A162862, A217070-A217089. (numbers b such that (b^p-1)/(b-1) is prime for prime p = 3 to 97)
A126589 gives locations of zeros.

Programs

  • Mathematica
    Table[Function[m, If[m > 0, k = 3; While[! PrimeQ[(m^k - 1)/(m - 1)], k++]; k, 0]]@ If[Set[e, GCD @@ #[[All, -1]]] > 1, {#, IntegerExponent[n, #]} &@ Power[n, 1/e] /. {{k_, m_} /; Or[Not[PrimePowerQ@ m], Prime@ m, FactorInteger[m][[1, 1]] == 2] :> 0, {k_, m_} /; m > 1 :> n}, n] &@ FactorInteger@ n, {n, 2, 17}] (* Michael De Vlieger, Apr 24 2017 *)
  • PARI
    a052409(n) = my(k=ispower(n)); if(k, k, n>1)
    a052410(n) = if (ispower(n, , &r), r, n)
    is(n) = issquare(n) || (ispower(n) && !ispseudoprime((n^a052410(a052409(n))-1)/(n-1)))
    a(n) = if(is(n), 0, forprime(p=3, 2^16, if(ispseudoprime((n^p-1)/(n-1)), return(p)))) \\ Eric Chen, Jun 01 2015, corrected by Eric Chen, Jun 04 2018, after Charles R Greathouse IV in A052409 and Michel Marcus in A052410

Extensions

a(18) = 25667 found by Henri Lifchitz, Sep 26 2007

A123487 Smallest prime q such that (q^p-1)/(q-1) is prime, where p = prime(n); or 0 if no such prime q exists.

Original entry on oeis.org

2, 2, 2, 2, 5, 2, 2, 2, 113, 151, 2, 61, 53, 89, 5, 307, 19, 2, 491, 3, 11, 271, 41, 2, 271, 359, 3, 2, 79, 233, 2, 7, 13, 11, 5, 29, 71, 139, 127, 139, 2003, 5, 743, 673, 593, 383, 653, 661, 251, 6389, 2833, 223, 163, 37, 709, 131, 41, 2203, 941, 2707, 13, 1283, 383
Offset: 1

Views

Author

Alexander Adamchuk, Sep 30 2006, Oct 02 2006

Keywords

Comments

Corresponding primes (q^p-1)/(q-1) are listed in A123488.
a(n) coincides with A066180(n) when A066180(n) is prime or 0.
From Robert G. Wilson v, Dec 28 2016: (Start)
Conjecture: Never is a(n) equal to 0.
Records: 2, 5, 113, 151, 307, 491, 2003, 6389, 7883, 11813, 18587, 31721, 40763, ... ;
First occurrence of the k_th prime: 1, 20, 5, 32, 21, 33, 81, 17, ... ;
Positions where two occurs: 1, 2, 3, 4, 6, 7, 8, 11, 18, 24, 28, 31, 98, 111, ... ;
Positions where three occurs: 20, 27, 100, 182, ... ;
Positions where five occurs: 5, 15, 35, 42, 114, 158, ... ; etc. (End)
Jones & Zvonkin conjecture (as did Robert G. Wilson v above) that a(n) > 0 for all n. - Charles R Greathouse IV, Jul 23 2021

Crossrefs

Programs

  • Mathematica
    f[n_] := NestWhile[NextPrime, 2, ! PrimeQ[Cyclotomic[Prime[n], #]] &]; Array[f, 63](* Davin Park, Dec 28 2016 and Robert G. Wilson v, Dec 28 2016 *)
  • PARI
    a(n) = {my(x = 2); while (!isprime(polcyclo(prime(n), x)), x= nextprime(x+1)); x;} \\ Michel Marcus, Dec 10 2016

A085399 Let Cn(x) be the n-th cyclotomic polynomial; a(n) is the first prime Cn(x) after Cn(1).

Original entry on oeis.org

2, 3, 7, 5, 31, 3, 127, 17, 73, 11, 12207031, 13, 8191, 43, 151, 257, 131071, 46441, 524287, 61681, 368089, 683, 11111111111111111111111, 241, 705429635566498619547944801, 2731, 262657, 15790321, 7369130657357778596659, 331, 2147483647, 65537, 599479, 43691
Offset: 1

Views

Author

Don Reble, Jun 28 2003

Keywords

Examples

			a(11)=12207031 because C11(x) is composite for x=2,3,4 and C11(5)=12207031 is prime.
		

Crossrefs

Formula

a(n) = Phi(n,A085398(n)) where Phi(n,k) is the n-th cyclotomic polynomial evaluated at k. - Jinyuan Wang, Sep 04 2022

Extensions

More terms from Jinyuan Wang, Sep 04 2022

A123488 Smallest prime of the form (q^p-1)/(q-1), where p = prime(n) and q is also prime (q = A123487(n)).

Original entry on oeis.org

3, 7, 31, 127, 12207031, 8191, 131071, 524287, 1484520425576434196455942238665054573307722183, 10333327940128053377465393536117755205850522803739374960650929
Offset: 1

Views

Author

Alexander Adamchuk, Sep 30 2006

Keywords

Comments

Corresponding smallest primes q are listed in A123487.
a(n) coincides with A084732(n) when A066180(n) is prime or 0.

Crossrefs

Formula

a(n) = (A123487(n)^prime(n) - 1) / (A123487(n) - 1).
Showing 1-5 of 5 results.