cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A092520 Number of square divisors of n-th cube: a(n) = A046951(n^3).

Original entry on oeis.org

1, 2, 2, 4, 2, 4, 2, 5, 4, 4, 2, 8, 2, 4, 4, 7, 2, 8, 2, 8, 4, 4, 2, 10, 4, 4, 5, 8, 2, 8, 2, 8, 4, 4, 4, 16, 2, 4, 4, 10, 2, 8, 2, 8, 8, 4, 2, 14, 4, 8, 4, 8, 2, 10, 4, 10, 4, 4, 2, 16, 2, 4, 8, 10, 4, 8, 2, 8, 4, 8, 2, 20, 2, 4, 8, 8, 4, 8, 2, 14, 7, 4, 2, 16, 4, 4, 4, 10, 2, 16, 4, 8, 4, 4, 4, 16
Offset: 1

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Author

Reinhard Zumkeller, Apr 06 2004

Keywords

Comments

Apparently the inverse Mobius transform of A056624 (and therefore multiplicative). - R. J. Mathar, Feb 07 2011

Examples

			For n=12, the divisors of 12^3 = 1728 are 1 = 1^2, 2, 3, 4 = 2^2, 6, 8, 9 = 3^2, 12, 16 = 4^2, 18, 24, 27, 32, 36 = 6^2, 48, 54, 64 = 8^2, 72, 96, 108, 144 = 12^2, 192, 216, 288, 432, 576 = 24^2, 864 and 1728: eight of them are squares, therefore a(12) = 8.
		

Crossrefs

Programs

Formula

a(n) = A000005(n) iff n is squarefree.
From Werner Schulte, Feb 19 2018: (Start)
Multiplicative with a(p^e) = floor((3*e+2)/2) = A001651(e+1), p prime and e >= 0.
Dirichlet g.f.: Sum_{n>0} a(n)/n^s = (zeta(s))^2 * zeta(2*s) / zeta(3*s). (End)
Sum_{k=1..n} a(k) ~ Pi^2 * n/(6*zeta(3)) * (log(n) - 1 + 2*gamma + 12*zeta'(2)/Pi^2 - 3*zeta'(3)/zeta(3)) + zeta(1/2)^2 * sqrt(n) / zeta(3/2), where gamma is the Euler-Mascheroni constant A001620. - Vaclav Kotesovec, Feb 08 2019