A099129 Let T(n) be the n-th triangular number n*(n+1)/2; then a(n) = n-th iteration T(T(T(...(n)))).
0, 1, 6, 231, 1186570, 347357071281165, 2076895351339769460477611370186681, 143892868802856286225154411591351342616163027795335641150249224655238508171
Offset: 0
Examples
a(3) = 231 because we can write the 3-time iterated expression on T(3), the triangular number sequence n*(n+1)/2, namely: T(T(T(3))) = 231.
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..10
Programs
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Maple
a:= n-> (t-> (t@@n)(n))(j-> j*(j+1)/2): seq(a(n), n=0..7); # Alois P. Heinz, Sep 29 2023
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Mathematica
Table[Nest[(#(#+1))/2&,n,n],{n,8}] (* Harvey P. Dale, May 29 2013 *)
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PARI
a(n) = my(k = n); for (j=1, n, k = k*(k+1)/2;); k; \\ Michel Marcus, Jan 01 2017
Formula
a(n) = A000217^n(n).
The sequence grows like O(n^2^n*1/2^n). This can be derived from the growth O(n^2*1/2) of the triangle sum by iteration. - Hieronymus Fischer, Jan 21 2006
Extensions
Offset changed to 1 by Georg Fischer, Jun 20 2022
a(0)=0 prepended by Alois P. Heinz, Sep 29 2023
Comments