A103562 -id:A103562 - cp's OEIS frontend

A030198 a(n) = n^((n+1)^(n+2)).

0, 1, 2417851639229258349412352

Offset: 0

Ian S. Elliott (ie3(AT)uenics.evansville.edu)

nonn

The next four terms have 489, 9408, 195667 and 4485888 digits respectively and are too large to include. - Rick L. Shepherd, May 07 2006

Amiram Eldar, Table of n, a(n) for n = 0..3

Cf. A103562.

Table[n^(n+1)^(n+2),{n,0,3}] (* Vladimir Joseph Stephan Orlovsky, Mar 14 2011 *)

A365689 Final decimal digit of n^((n+1)^(n+2)) = A030198(n).

Original entry on oeis.org

0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6

Offset: 0

Marco Ripà, Sep 16 2023

Period 10, repeat: [0, 1, 2, 1, 4, 5, 6, 1, 8, 1].

			For n = 2, a(2) = 2417851639229258349412352 mod 10 = 2.

Paolo Xausa, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,0,1).

Cf. A030198, A103562, A120962, A365689 (initial digit).

PadRight[{},100,{0,1,2,1,4,5,6,1,8,1}] (* Paolo Xausa, Oct 16 2023 *)

a(n) = lift(Mod(n, 10)^((n+1)^(n+2))); \\ Michel Marcus, Sep 16 2023

def A365689(n): return pow(n,(n+1)**(n+2),10) # Chai Wah Wu, Sep 22 2023

a(n) = n^((n+1)^(n+2)) mod 10.
a(n) = A103562(n) for n >= 4 (as 3^(2^1) == 9 (mod 10) instead of 1).
G.f.: x*(x^8+8*x^7+x^6+6*x^5+5*x^4+4*x^3+x^2+2*x+1)/(1-x^10). - Alois P. Heinz, Apr 18 2025

cp's OEIS Frontend

A030198 a(n) = n^((n+1)^(n+2)).

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A365689 Final decimal digit of n^((n+1)^(n+2)) = A030198(n).

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