A117402 Row sums of triangle A117401: a(n) = Sum_{k=0..n} 2^((n-k)*k) for n>=0.
1, 2, 4, 10, 34, 162, 1090, 10370, 139522, 2654722, 71435266, 2718435330, 146299424770, 11134711111682, 1198484887715842, 182431106853797890, 39271952800672710658, 11955805018770498519042, 5147453397489773531365378
Offset: 0
Keywords
Examples
A(x) = 1/(1-x) + x/(1-2x) + x^2/(1-4x) + x^3/(1-8x) + ...
References
- R. P. Stanley, Enumerative Combinatorics, Volume I, Second Edition, Cambridge, 2012, Example 3.18.3 e, page 323.
Links
- Robert Israel, Table of n, a(n) for n = 0..116
Programs
-
Magma
[(&+[2^(k*(n-k)): k in [0..n]]): n in [0..20]]; // G. C. Greubel, Jun 28 2021
-
Maple
N:= 25: G:= series(add(x^n/(1-2^n*x),n=0..N),x,N+1): seq(coeff(G,x,n),n=0..N)); # Robert Israel, Dec 11 2018
-
Mathematica
a[n_]:= Sum[2^((n-k)*k), {k,0,n}]; Array[a, 20, 0] (* Amiram Eldar, Dec 12 2018 *)
-
PARI
a(n)=sum(k=0,n,2^((n-k)*k))
-
Sage
[sum(2^(k*(n-k)) for k in (0..n)) for n in (0..20)] # G. C. Greubel, Jun 28 2021
Formula
G.f.: A(x) = Sum_{n>=0} x^n/(1-2^n*x).
Let E(x) = Sum_{n>=0} x^n/2^C(n,2). Then E(x)^2 = Sum_{n>=0} a(n)*x^n/2^C(n,2). - Geoffrey Critzer, May 31 2020
a(n) ~ c * 2^(n^2/4), where c = EllipticTheta[3, 0, 1/2] = JacobiTheta3(0,1/2) = 2.128936827211877158669458548544951324612516539940878092889... if n is even and c = EllipticTheta[2, 0, 1/2] = JacobiTheta2(0,1/2) = 2.128931250513027558591613402575350180853805396958448940969... if n is odd. - Vaclav Kotesovec, Jun 28 2021
Comments