A118188 Column 0 of the matrix inverse of triangle A118185(n,k) = (4^k)^(n-k).
1, -1, 3, -33, 1407, -237057, 158992383, -425715556353, 4556004503093247, -194971932801554579457, 33370662957719457037287423, -22845215336421444625717664940033, 62557106610069521429900219032249827327, -685195337175488637158242110253091749621661697
Offset: 0
Keywords
Examples
Recurrence at n=4: 0 = a(0)*(4^0)^4 +a(1)*(4^1)^3 +a(2)*(4^2)^2 +a(3)*(4^3)^1 +a(4)*(4^4)^0 = 1*(4^0) - 1*(4^3) + 3*(4^4) - 33*(4^3) + 1407*(4^0). The g.f. is illustrated by: 1 = 1/(1-x) - 1*x/(1-4*x) + 3*x^2/(1-16*x) - 33*x^3/(1-64*x) + 1407*x^4/(1-256*x) - 237057*x^5/(1-1024*x) + 158992383*x^6/(1-4096*x) +...
Links
- G. C. Greubel, Table of n, a(n) for n = 0..55
Crossrefs
Cf. A118185 (triangle).
Programs
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Mathematica
a[n_]:= a[n]= If[n<2, (-1)^n, -Sum[4^(j*(n-j))*a[j], {j, 0, n-1}]]; Table[a[n], {n, 0, 30}] (* G. C. Greubel, Jun 29 2021 *)
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PARI
{a(n)=local(T=matrix(n+1,n+1,r,c,if(r>=c,(4^(c-1))^(r-c)))); return((T^-1)[n+1,1])}
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Sage
@CachedFunction def a(n): return (-1)^n if (n<2) else -sum(4^(j*(n-j))*a(j) for j in (0..n-1)) [a(n) for n in (0..30)] # G. C. Greubel, Jun 29 2021
Formula
G.f.: 1 = Sum_{n>=0} a(n)*x^n/(1-4^n*x).
0^n = Sum_{k=0..n} a(k)*4^(k*(n-k)) for n>=0.
G.f.: Sum_{n>=0} a(n)*x^n/2^(n^2) = 1/Sum_{n>=0} x^n/2^(n^2). - Vladeta Jovovic, Oct 14 2009
a(n) = (-1)*Sum_{j=0..n-1} 4^(j*(n-j))*a(j) with a(0) = 1, and a(1) = -1. - G. C. Greubel, Jun 29 2021
a(n) ~ (-1)^n * c * d^n * 2^(n^2), where d = 0.3264264803687260917234459979520857231773098381012486773185370058835770869... and c = 1.9166236268503386759188959219480676595889651334615223163023463792603010986... - Vaclav Kotesovec, Jun 09 2025
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