A119704 a(n) = number of distinct prime factors of 10^n+1 = omega(10^n+1).
1, 1, 1, 3, 2, 2, 2, 2, 2, 5, 3, 4, 3, 3, 4, 7, 5, 4, 3, 2, 4, 7, 4, 5, 3, 5, 3, 7, 4, 3, 7, 2, 4, 8, 4, 5, 6, 4, 3, 9, 4, 3, 7, 4, 4, 12, 4, 4, 9, 4, 7, 8, 4, 2, 6, 9, 5, 6, 5, 4, 6, 3, 3, 11, 3, 6, 8, 2, 4, 10, 11, 3, 5, 4, 7, 11, 6, 11, 7, 4, 9, 11, 3, 7, 8, 8, 3, 8, 4, 4, 11, 6, 4, 8, 4, 6, 8, 4
Offset: 0
Keywords
Examples
a(1) = number of distinct prime factors of 11 = 1. a(3) = number of distinct prime factors of 1001 = 3. a(11) = 4 because 10^11+1 = 11*11*23*4093*8779 has 4 distinct factors.
Links
- Max Alekseyev, Table of n, a(n) for n = 0..331 [First 309 terms from Ray Chandler, from the Kamada link]
- Makoto Kamada, Factorizations of 100...001.
Programs
-
Mathematica
Table[Length[FactorInteger[10^n + 1]], {n, 0, 50}] (* Stefan Steinerberger, Jun 13 2006 *) PrimeNu[10^Range[0,100]+1] (* The program will take some time to run *) (* Harvey P. Dale, Aug 27 2019 *)
Formula
Extensions
More terms from Don Reble, Jun 13 2006