A120112 Row sums of number triangle A120111.
1, -1, -2, -1, -4, 0, -6, -1, -2, 0, -10, 0, -12, 0, 0, -1, -16, 0, -18, 0, 0, 0, -22, 0, -4, 0, -2, 0, -28, 0, -30, -1, 0, 0, 0, 0, -36, 0, 0, 0, -40, 0, -42, 0, 0, 0, -46, 0, -6, 0, 0, 0, -52, 0, 0, 0, 0, 0, -58, 0, -60, 0, 0, -1, 0, 0, -66, 0, 0, 0, -70, 0, -72
Offset: 0
Links
- Muniru A Asiru, Table of n, a(n) for n = 0..5000
Programs
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GAP
Concatenation([1],List([1..70],n->1-Lcm(List([1..n+1],i->i))/Lcm(List([1..n],i->i)))); # Muniru A Asiru, Mar 04 2019
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Magma
A120112:= func< n | n eq 0 select 1 else 1-Lcm([1..n+1])/Lcm([1..n]) >; [A120112(n): n in [0..100]]; // G. C. Greubel, May 05 2023
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Mathematica
Table[If[n==0, 1, 1-LCM@@Range[n+1]/(LCM@@Range[n])], {n,0,100}] (* G. C. Greubel, May 05 2023 *)
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PARI
a(n) = if (n==0, 1, 1 - lcm(vector(n+1, k, k))/lcm(vector(n, k, k))); \\ Michel Marcus, Sep 11 2016
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SageMath
def A120112(n): return 1 if n == 0 else 1 - lcm(range(1,n+2)) // lcm(range(1,n+1)) [A120112(n) for n in range(101)] # G. C. Greubel, May 05 2023
Formula
a(n) = 1 - lcm(1,...,n+1)/lcm(1,...,n) for n > 0.
a(n) = 1 - A014963(n+1). - Joerg Arndt, Sep 12 2016
Comments