A138099 Irregular triangle read by rows: T(n,k) = k + floor(n/2), 1 <= k <= ceiling(n/2).
1, 2, 2, 3, 3, 4, 3, 4, 5, 4, 5, 6, 4, 5, 6, 7, 5, 6, 7, 8, 5, 6, 7, 8, 9, 6, 7, 8, 9, 10, 6, 7, 8, 9, 10, 11, 7, 8, 9, 10, 11, 12, 7, 8, 9, 10, 11, 12, 13, 8, 9, 10, 11, 12, 13, 14, 8, 9, 10, 11, 12, 13, 14, 15, 9, 10, 11, 12, 13, 14, 15, 16, 9, 10, 11, 12, 13
Offset: 1
Examples
Triangle begins: 1; 2; 2, 3; 3, 4; 3, 4, 5; 4, 5, 6; 4, 5, 6, 7; 5, 6, 7, 8; ...
Programs
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Magma
lst:=[]; for n in [1..16] do for k in [1..Ceiling(n/2)] do Append(~lst, k+Floor(n/2)); end for; end for; lst; // Arkadiusz Wesolowski, Jun 15 2014
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Mathematica
Table[k+Floor[n/2],{n,20},{k,Ceiling[n/2]}]//Flatten (* Harvey P. Dale, Aug 15 2017 *)
Formula
a(n) = n - floor((1/4)*(floor(sqrt(4*n-3))-1)^2). - Mircea Merca, Feb 05 2012
From Benedict W. J. Irwin, May 14 2016: (Start)
Conjecture: a(n) = HookSum(T(n))-HookSum(T(n-1)), where HookSum(A) is the sum of all hooks across a tableau A, and T(n) are the spiraling sequence of tableaux:
o oo ooo
Empty, o, oo, oo, oo, oo , ooo , ooo, ooo, ooo, ...
o oo ooo ooo ooo ooo ooo
(End)
Extensions
Name changed and more terms added by Arkadiusz Wesolowski, Jun 15 2014
Comments