cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A014623 Sequence arising from analysis of Levine's sequence A011784: essentially a duplicate of A144005.

Original entry on oeis.org

1, 1, 2, 7, 33, 201, 1479, 12842, 127952
Offset: 0

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Author

Keywords

Comments

Presumably this is the same as A144005.
Yes, I can confirm that. On Aug 28 1997 Colin Mallows wrote to me saying he obtained the present sequence (A014623) by inverting - or reverting - Levine's sequence A011784 using the tables in David-Kendall-Barton (1966). - N. J. A. Sloane, Jul 24 2022

References

  • F. N. David, M. G. Kendall and D. E. Barton, Symmetric Function and Allied Tables, Cambridge, 1966.

Crossrefs

A144005 is a better version - N. J. A. Sloane, Jul 24 2022
Cf. A011784.

A144006 Triangle, read by rows of coefficients of x^n*y^k for k=0..n(n-1)/2 for n>=0, defined by e.g.f.: A(x,y) = 1 + Series_Reversion( Integral A(-x*y,y) dx ), with leading zeros in each row suppressed.

Original entry on oeis.org

1, 1, 1, 3, -1, 15, -10, 3, -1, 105, -105, 55, -30, 10, -3, 1, 945, -1260, 910, -630, 350, -168, 76, -30, 10, -3, 1, 10395, -17325, 15750, -12880, 9135, -5789, 3381, -1806, 910, -434, 196, -76, 30, -10, 3, -1, 135135, -270270, 294525, -275275, 228375
Offset: 0

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Author

Paul D. Hanna, Sep 10 2008

Keywords

Comments

Comment from Lucas Larsen, Aug 20 2024: (Start)
The nonzero entries in the n-th row appear to be the nonzero coefficients (up to sign) in the following:
Let c be a fixed point in (0,oo) and f a smooth function such that f(c) = c and f(f'(x)) = x in a neighborhood of c. Then the n-th derivative of f evaluated at c can be written as a Laurent polynomial in c with the (descending) coefficients in question.
For instance:
f'(c) = c
f''(c) = c^(-1)
f'''(c) = -c^(-4)
f''''(c) = 3c^(-7) + c^(-8)
(End)

Examples

			Triangle begins (without suppressing leading zeros):
1;
1;
0, 1;
0,0, 3, -1;
0,0,0, 15, -10, 3, -1;
0,0,0,0, 105, -105, 55, -30, 10, -3, 1;
0,0,0,0,0, 945, -1260, 910, -630, 350, -168, 76, -30, 10, -3, 1;
0,0,0,0,0,0, 10395, -17325, 15750, -12880, 9135, -5789, 3381, -1806, 910, -434, 196, -76, 30, -10, 3, -1;
0,0,0,0,0,0,0, 135135, -270270, 294525, -275275, 228375, -172200, 120960, -78519, 48006, -28336, 16065, -8609, 4461, -2166, 1018, -470, 196, -76, 30, -10, 3, -1; ...
		

Crossrefs

Generates A014621, A014622 and A014623, which are related to Levine's sequence A011784.

Programs

  • PARI
    {T(n,k)=local(A=1+x*O(x^n)); for(i=0,n,A=1+serreverse(intformal(subst(A,x,-x*y))));n!*polcoeff(polcoeff(A,n,x),k,y)}
    
  • Python
    #This is only correct if the observation in the comment from 2024/08/20 is true.
    def T(n,k):
        if 0 <= n <= 1:
            return 1 if k == 0 else 0
        c = {(-1,):1} #Polynomial in infinitely many variables (function iterates)
        for _ in range(n-1):
            cnext = {}
            for key, value in c.items():
                key += (0,)
                for i, ni in enumerate(key):
                    term = tuple(nj-2 if j==i else nj-1 if j<=i+1 else nj
                                 for j,nj in enumerate(key))
                    cnext[term] = cnext.get(term,0) + value*ni
                    if cnext[term] == 0:
                        del cnext[term]
            c = cnext
        pairs = {} #Reduction to single variable (evaluation at fixpoint)
        for key, value in c.items():
            s = -sum(key)
            pairs[s] = pairs.get(s,0) + value
        _, row = zip(*sorted(pairs.items())) #Coefficients
        if 0 <= k-n+1 < len(row): #Correcting number of leading 0s
            return (-1)**(n+k+1)*abs(row[k-n+1]) #Correcting signs
        else:
            return 0
    # Lucas Larsen, Aug 22 2024

Formula

E.g.f. satisfies: A(x,y) = 1 + Series_Reversion[Integral A(-x*y,y) dx].
T(n,k) = [x^n*y^k] n!*A(x,y) for k=0..n(n-1)/2, n>=0.
Row sums equal A144005.
A067146(n) = Sum_{k=0..n(n-1)/2} (-1)^k*T(n,k).
This is a signed version of table A014621 because setting f((1+x)/y):=A(-x*y,y)/y for fixed y>0 implies f(f(x))*f'(x)=-1 and f(1/y)=1/y, as in the second formula of A014621. Therefore, the row sums form A014623 and the unsigned row sums form A014622. - Roland Miyamoto, Jun 03 2024
Showing 1-2 of 2 results.