A155724 Triangle read by rows: T(n, k) = 2*n*k + n + k - 4.
0, 3, 8, 6, 13, 20, 9, 18, 27, 36, 12, 23, 34, 45, 56, 15, 28, 41, 54, 67, 80, 18, 33, 48, 63, 78, 93, 108, 21, 38, 55, 72, 89, 106, 123, 140, 24, 43, 62, 81, 100, 119, 138, 157, 176, 27, 48, 69, 90, 111, 132, 153, 174, 195, 216, 30, 53, 76, 99, 122, 145, 168, 191, 214, 237, 260
Offset: 1
Examples
Triangle begins: 0; 3, 8; 6, 13, 20; 9, 18, 27, 36; 12, 23, 34, 45, 56; 15, 28, 41, 54, 67, 80; 18, 33, 48, 63, 78, 93, 108; 21, 38, 55, 72, 89, 106, 123, 140; 24, 43, 62, 81, 100, 119, 138, 157, 176; 27, 48, 69, 90, 111, 132, 153, 174, 195, 216;
Links
- Vincenzo Librandi, Rows n = 1..100, flattened
Crossrefs
Programs
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Magma
/* Triangle: */ [[2*m*n+m+n-4: m in [1..n]]: n in [1..10]]; // Bruno Berselli, Aug 31 2012
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Mathematica
Flatten[Table[2 n m + m + n - 4, {n, 10}, {m, n}]] (* Vincenzo Librandi, Mar 01 2012 *)
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Python
def A155724(n,k): return 2*n*k+n+k-4 print(flatten([[A155724(n,k) for k in range(1,n+1)] for n in range(1,16)])) # G. C. Greubel, Jan 21 2025
Formula
T(n, k) = A154685(n, k) - 8. - L. Edson Jeffery, Oct 12 2012
2*T(n, k) + 9 = (2*k+1)*(2*n+1). - Vincenzo Librandi, Nov 18 2012
From G. C. Greubel, Jan 21 2025: (Start)
T(2*n-1, n) = 4*n^2 + n - 5 (main diagonal).
Sum_{k=1..n} (-1)^(k-1)*T(n, k) = (1/4)*( 4*(-1)^(n+1)*n^2 + 2*(2-3*(-1)^n)*n - 7*(1-(-1)^n)).
G.f.: x*y*(3*x + 3*y - 4*x*y)/((1-x)*(1-y))^2. (End)
Extensions
Edited by N. J. A. Sloane, Jun 23 2010