cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 10 results.

A176764 Smallest power of 4 whose decimal expansion contains n.

Original entry on oeis.org

1024, 1, 256, 16384, 4, 256, 16, 1048576, 16384, 4096, 1024, 1099511627776, 1125899906842624, 1180591620717411303424, 262144, 288230376151711744, 16, 17179869184, 1073741824, 4194304, 72057594037927936, 262144, 4722366482869645213696
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 4 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 4^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 256 because 4^4 = 256 has "2" as a substring.
a(3) = 16384 because 4^7 = 16384 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176764[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[4^++k], IntegerString[n]]]; 4^k]; Array[A176764, 50, 0] (* Paolo Xausa, Apr 03 2024 *)

Formula

a(n) = MIN{A000302(i) such that n in decimal representation is a substring of A000302(i)}.
a(n) = 4^A062521(n). - Michel Marcus, Sep 30 2014

Extensions

Corrected and extended by Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 03 2024

A176765 Smallest power of 5 whose decimal expansion contains n.

Original entry on oeis.org

390625, 1, 25, 3125, 48828125, 5, 625, 78125, 78125, 390625, 6103515625, 11920928955078125, 125, 931322574615478515625, 244140625, 15625, 95367431640625, 30517578125, 2384185791015625, 1953125, 1220703125, 116415321826934814453125
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 5 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 5^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 25 because 5^2 = 25 has "2" as a substring.
a(3) = 3125 because 5^5 = 3125 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176765[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[5^++k], IntegerString[n]]]; 5^k]; Array[A176765, 50, 0] (* Paolo Xausa, Apr 03 2024 *)

Formula

a(n) = MIN{A000351(i) such that n in decimal representation is a substring of A000351(i)}.
a(n) = 5^A062522(n). - Michel Marcus, Sep 30 2014

Extensions

Corrected comment by Sean A. Irvine, May 05 2010
More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 03 2024

A176767 Smallest power of 7 whose decimal expansion contains n.

Original entry on oeis.org

2401, 1, 2401, 343, 49, 823543, 16807, 7, 16807, 49, 96889010407, 117649, 13841287201, 13841287201, 11398895185373143, 4747561509943, 16807, 117649, 11398895185373143, 1977326743, 13841287201, 3909821048582988049
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 7 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 7^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 2401 because 7^4 = 2401 has "2" as a substring.
a(3) = 343 because 7^3 = 343 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176767[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[7^++k], IntegerString[n]]]; 7^k]; Array[A176767, 50, 0] (* Paolo Xausa, Apr 03 2024 *)

Formula

a(n) = MIN{A000420(i) such that n in decimal representation is a substring of A000420(i)}.
a(n) = 7^A062524(n). - Michel Marcus, Sep 30 2014

Extensions

More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
Extended to a(0) by M. F. Hasler, Oct 03 2014

A176768 Smallest power of 8 whose decimal expansion contains n.

Original entry on oeis.org

4096, 1, 512, 32768, 64, 512, 64, 32768, 8, 4096, 1073741824, 4398046511104, 512, 134217728, 262144, 2097152, 16777216, 134217728, 1073741824, 68719476736, 2097152, 262144, 2251799813685248, 9223372036854775808, 1073741824
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 8 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 8^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 512 because 8^3 = 512 has "2" as a substring.
a(3) = 32768 because 8^5 = 32768 has "3" as a substring.
		

Crossrefs

Programs

  • Maple
    F:= proc(dmax) local R,count,x,N,L,d,i,v;
    count:= 0: x:= 1/8: N:= 10^dmax:
    while count < N do
      x:= 8*x;
      L:= convert(x,base,10);
      for d from 1 to min(dmax, nops(L)) do
        for i from 1 to nops(L)-d+1 do
          v:= add(L[j]*10^(j-i),j=i..i+d-1);
          if not assigned(R[v]) then count:= count+1; R[v]:= x fi
    od od od:
    seq(R[v],v=0..N-1);
    end proc:
    F(2); # Robert Israel, Dec 25 2019
  • Mathematica
    A176768[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[8^++k], IntegerString[n]]]; 8^k]; Array[A176768, 50, 0] (* Paolo Xausa, Apr 04 2024 *)

Formula

a(n) = MIN{A001018(i) such that n in decimal representation is a substring of A001018(i)}.
a(n) = 8^A062525(n). - Michel Marcus, Sep 30 2014

Extensions

More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0)=4096 inserted by Robert Israel, Dec 25 2019

A186774 Smallest power of n whose decimal expansion contains n+1, or 0 if no such number exists.

Original entry on oeis.org

32, 243, 256, 625, 7776, 16807, 4096, 31381059609, 0, 121, 79496847203390844133441536, 51185893014090757, 155568095557812224, 22168378200531005859375, 17592186044416, 118587876497, 11019960576, 42052983462257059
Offset: 2

Views

Author

Jonathan Vos Post, Feb 26 2011

Keywords

Comments

More precisely: smallest power of n (with positive integer exponent) whose decimal expansion contains n+1 as a substring of consecutive decimal digits. This is A[n,n+1], the diagonal above the trivial main diagonal of the array A[k,n] = Smallest power of k whose decimal expansion contains n.
The k=2 row A[2,n] = A030001.
The k=3 row A[3,n] = A176763.
The k=4 row A[4,n] = A176764.
The k=5 row A[5,n] = A176765...
a(10^k+1) = (10^k+1)^2 for k > 0. - Chai Wah Wu, Feb 13 2017

Examples

			a(2) = 32 = A030001(3) = smallest power of 2 whose decimal expansion contains 3.
a(3) = 243 = A176763(4) = smallest power of 3 whose decimal expansion contains 4.
		

Crossrefs

Programs

  • Maple
    a:= proc(n) local t, k;
          if type(simplify(log[10](n)), integer) then 0
        else t:= cat(n+1);
             for k from 2 while searchtext(t, cat(n^k))=0
             do od; n^k
          fi
        end:
    seq(a(n), n=2..40);  # Alois P. Heinz, Feb 26 2011
  • Python
    def A186774(n):
        if sum(int(d) for d in str(n)) == 1:
            return 0
        sn, k = str(n+1), 1
        while sn not in str(k):
            k *= n
        return k # Chai Wah Wu, Feb 13 2017

A176766 Smallest power of 6 whose decimal expansion contains n.

Original entry on oeis.org

10077696, 1, 216, 36, 46656, 46656, 6, 7776, 2176782336, 1296, 10077696, 2821109907456, 1296, 13060694016, 6140942214464815497216, 101559956668416, 216, 60466176, 470184984576, 21936950640377856, 170581728179578208256, 216
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 6 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 6^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 216 because 6^3 = 216 has "2" as a substring.
a(3) = 36 because 6^2 = 36 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176766[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[6^++k], IntegerString[n]]]; 6^k]; Array[A176766, 50, 0] (* Paolo Xausa, Apr 03 2024 *)

Formula

a(n) = MIN{A000400(i) such that n in decimal representation is a substring of A000400(i)}.
a(n) = 6^A062523(n). - Michel Marcus, Sep 30 2014

Extensions

Corrected and extended by Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 03 2024

A176769 Smallest power of 9 whose decimal expansion contains n.

Original entry on oeis.org

59049, 1, 729, 531441, 59049, 6561, 6561, 729, 81, 9, 31381059609, 205891132094649, 150094635296999121, 31381059609, 531441, 150094635296999121, 16677181699666569, 1350851717672992089, 2541865828329, 8862938119652501095929
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 9 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 9^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 729 because 9^3 = 729 has "2" as a substring.
a(3) = 531441 because 9^6 = 531441 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176769[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[9^++k], IntegerString[n]]]; 9^k]; Array[A176769, 50, 0] (* Paolo Xausa, Apr 04 2024 *)

Formula

a(n) = MIN{A001019(i) such that n in decimal representation is a substring of A001019(i)}.
a(n) = 9^A062526(n). - Michel Marcus, Sep 30 2014

Extensions

More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 04 2024

A176770 Smallest power of 11 whose decimal expansion contains n.

Original entry on oeis.org

161051, 1, 121, 1331, 14641, 161051, 14641, 1771561, 19487171, 19487171, 161051, 11, 121, 1331, 14641, 1771561, 161051, 1771561, 9849732675807611094711841, 19487171, 672749994932560009201, 121, 34522712143931, 2357947691, 25937424601
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 11 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 11^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 121 because 11^2 = 121 has "2" as a substring.
a(3) = 1331 because 11^3 = 1331 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176770[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[11^++k], IntegerString[n]]]; 11^k]; Array[A176770, 50, 0] (* Paolo Xausa, Apr 04 2024 *)

Formula

a(n) = MIN{A001020(i) such that n in decimal representation is a substring of A001020(i)}.

Extensions

More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 04 2024

A176771 Smallest power of 12 whose decimal expansion contains n.

Original entry on oeis.org

20736, 1, 12, 20736, 144, 2985984, 20736, 1728, 1728, 2985984, 8916100448256, 2218611106740436992, 12, 79496847203390844133441536, 144, 5159780352, 429981696, 1728, 35831808, 61917364224, 20736, 15407021574586368
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 12 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 12^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 12 because 12^1 = 12 has "2" as a substring.
a(3) = 20736 because 12^4 = 20736 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176771[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[12^++k], IntegerString[n]]]; 12^k]; Array[A176771, 50, 0] (* Paolo Xausa, Apr 04 2024 *)

Formula

a(n) = MIN{A001021(i) such that n in decimal representation is a substring of A001021(i)}.

Extensions

More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 04 2024

A176772 Smallest power of 13 whose decimal expansion contains n.

Original entry on oeis.org

4826809, 1, 2197, 13, 4826809, 28561, 169, 2197, 28561, 169, 10604499373, 51185893014090757, 371293, 13, 51185893014090757, 815730721, 169, 62748517, 137858491849, 2197, 1461920290375446110677, 2197, 23298085122481
Offset: 0

Views

Author

Jonathan Vos Post, Apr 25 2010

Keywords

Comments

This is to 13 as A176763 is to 3 and as A030001 is to 2.

Examples

			a(1) = 1 because 13^0 = 1 has "1" as a substring (not a proper substring, though).
a(2) = 2197 because 13^3 = 2197 has "2" as a substring.
a(3) = 13 because 13^1 = 13 has "3" as a substring.
		

Crossrefs

Programs

  • Mathematica
    A176772[n_] := Block[{k = -1}, While[StringFreeQ[IntegerString[13^++k], IntegerString[n]]]; 13^k]; Array[A176772, 50, 0] (* Paolo Xausa, Apr 04 2024 *)

Formula

a(n) = MIN{A001022(i) such that n in decimal representation is a substring of A001022(i)}.

Extensions

More terms from Sean A. Irvine and Jon E. Schoenfield, May 05 2010
a(0) prepended by Paolo Xausa, Apr 04 2024
Showing 1-10 of 10 results.