cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A131210 Numbers k such that 24k - 1 is prime.

Original entry on oeis.org

1, 2, 3, 7, 8, 10, 11, 13, 15, 16, 18, 20, 21, 25, 27, 30, 31, 35, 36, 37, 38, 41, 43, 46, 48, 51, 55, 57, 60, 62, 63, 65, 66, 67, 76, 77, 78, 85, 86, 87, 88, 92, 98, 100, 101, 102, 106, 108, 111, 112, 113, 120, 121, 122, 125, 126, 130, 132, 133, 140, 142, 147, 151, 153
Offset: 1

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Author

Zak Seidov, Oct 29 2007

Keywords

Comments

The complement is 4, 5, 6, 9, 12, 14, 17, 19, 22, 23, 24, ... and contains numbers of the form == 4 (mod 5), == 5 (mod 7), == 6 (mod 11), == 6 (mod 13), == 5 (mod 17) etc., so the complement is a superset of A182719. - R. J. Mathar, Jun 10 2020

Crossrefs

Cf. A182719.

Programs

A340757 Counterexamples to a conjecture of Ramanujan about congruences related to the partition function.

Original entry on oeis.org

243, 586, 1272, 2301, 2644, 2987, 3673, 4702, 5045, 5388, 6074, 7103, 7446, 7789, 8475, 9504, 9847, 10190, 10876, 11905, 12248, 12591, 13277, 14306, 14649, 14992, 15678, 16707, 17050, 17393, 18079, 19108, 19451, 19794, 20480, 21509, 21852, 22195, 22881, 23910
Offset: 1

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Author

Washington Bomfim, Jan 19 2021

Keywords

Comments

For b in 5,7,11, and all integers n,e >= 1, Ramanujan conjectured that if (24*n-1) is divisible by b^e, the partition function p(n) = A000041(n) is also divisible by b^e.
Chowla found the first counterexample a(1) = 243. Watson showed the conjecture holds for b=5, and Atkin showed it holds for b=11. Watson showed p(n) is divisible by 7^floor((d+2)/2) when 24n-1 is divisible by 7^d, so that exceptions here are restricted to 24n-1 == 0 (mod 7^3), which is n == 243 (mod 7^3).
See A340957 for the converse, those n == 243 (mod 7^3) where the conjecture does hold.

Examples

			243 is a term because for n = 243, the condition of Ramanujan (24*n - 1) divisible by b^e is true, and p(n) is not divisible by (b^e). [We have base b=7, and exponent e=3 in this case.] Since a(1) = A182719(91), 90 numbers satisfy the conjecture before the first counterexample a(1).
		

Crossrefs

Programs

  • PARI
    seq(x) = {my( n = -100, N=0); while(N < x, n += 343; if(valuation(numbpart(n),7) < valuation(24*n-1,7), print1(n", "); N++)) };
    seq(100); \\ Gives the first 100 terms of the sequence.

A194699 a(n) = floor((p - 1)/12) - floor((p^2 - 1)/(24*p)), where p = prime(n).

Original entry on oeis.org

0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 10, 10, 10, 10, 10, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 13, 14, 14, 14, 15, 15, 15, 15, 16, 16, 16, 16
Offset: 1

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Author

Omar E. Pol, Jan 18 2012

Keywords

Comments

Sequence related to Ramanujan's famous partition congruences modulo powers of 5, 7 and 11. Ramanujan wrote: "It appears there are no equally simple properties for any moduli involving primes other than these three". On the other hand the Folsom-Kent-Ono theorem said: for a prime L >= 5, the partition numbers are L-adically fractal. Moreover, the Hausdorff dimension is <= floor((L - 1)/12) - floor((L^2 - 1)/(24*L)). Also, the Folsom-Kent-Ono corollary said: the dim is 0 only for L = 5, 7, 11 and so we have: 1) Ramanujan's congruences powers of 5, 7 and 11. 2) There are no simple properties for any other primes.

Examples

			For primes 5, 7, 11 the Hausdorff dimension = 0, so a(3)..a(5) = 0.
For primes 13, 17, 19, 23, 29, 31 the Hausdorff dimension = 1, so a(6)..a(11) = 1.
		

Crossrefs

Formula

a(n) = A194698(A000040(n)).
a(n) ~ 0.125 n log n. [Charles R Greathouse IV, Jan 25 2012]
Showing 1-3 of 3 results.