A196791 a(n) = A047848(9, n).
1, 2, 14, 158, 1886, 22622, 271454, 3257438, 39089246, 469070942, 5628851294, 67546215518, 810554586206, 9726655034462, 116719860413534, 1400638324962398, 16807659899548766, 201691918794585182, 2420303025535022174, 29043636306420266078, 348523635677043192926
Offset: 0
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..900
- Index entries for linear recurrences with constant coefficients, signature (13,-12).
Crossrefs
Programs
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Magma
[(12^n+10)/11: n in [0..20]];
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Mathematica
LinearRecurrence[{13,-12},{1,2},30] (* Harvey P. Dale, Sep 07 2015 *) (12^Range[0,40] +10)/11 (* G. C. Greubel, Jan 17 2025 *)
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Python
def A196791(n): return (pow(12, n) + 10)//11 print([A196791(n) for n in range(41)]) # G. C. Greubel, Jan 17 2025
Formula
a(n) = (12^n + 10)/11.
a(n) = 12*a(n-1) - 10, with a(0) = 1.
G.f.: (1-11*x)/((1-x)*(1-12*x)). - Bruno Berselli, Oct 11 2011
From Elmo R. Oliveira, Aug 30 2024: (Start)
E.g.f.: exp(x)*(exp(11*x) + 10)/11.
a(n) = 13*a(n-1) - 12*a(n-2) for n > 1. (End)