cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A343597 Numbers divisible by a 7-smooth composite number.

Original entry on oeis.org

4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, 28, 30, 32, 35, 36, 40, 42, 44, 45, 48, 49, 50, 52, 54, 56, 60, 63, 64, 66, 68, 70, 72, 75, 76, 78, 80, 81, 84, 88, 90, 92, 96, 98, 99, 100, 102, 104, 105, 108, 110, 112, 114, 116, 117, 120, 124, 125, 126, 128, 130
Offset: 1

Views

Author

Peter Munn, Apr 21 2021

Keywords

Comments

Numbers divisible by at least one of 4, 6, 9, 10, 14, 15, 21, 25, 35, 49.
Exactly half of the first 10, first 100 and first 600 positive integers are divisible by a 7-smooth composite number; the largest 7-smooth divisor of the remaining numbers is 1, 2, 3, 5 or 7.
Intervals extending to hundreds of integers with exactly 50% membership of this sequence are far from rare, some notable examples being [3000, 3999], [8000, 8999], [20000, 20999], [21000, 21999] and [23000, 23999]. This reflects the asymptotic density of the corresponding set being close to 0.5, precisely 1847 / 3675 = 0.50258503... (and membership of the set has a periodic pattern). See A343598 for further information.

Examples

			33 = 11 * 3 has divisors 1, 3, 11, 33, of which only 33 is composite. 33 is not 7-smooth, as its prime factors include 11, which is greater than 7. So 33 is not in the sequence.
52 = 13 * 2 * 2 is divisible by 4, which is composite and 7-smooth, so 52 is in the sequence.
		

Crossrefs

Cf. A002473 (7-smooth numbers), A014673, A020639, A210615 (smallest smoothest composite divisor), A343598.
Subsequence of A080672.

Programs

  • Mathematica
    Select[Range[130], Plus @@ IntegerExponent[#, {2, 3, 5, 7}] > 1 &] (* Amiram Eldar, May 04 2021 *)

Formula

{a(n)} = {k : k >= 1, 2 <= A014673(k) <= 7}, where A014673(k) = lpf(k/lpf(k)), where lpf(m) = A020639(m), the least prime factor of m.
For n >= 1, a(22164 + n) = 44100 + a(n).
For n < 22164, a(22164 - n) = 44100 - a(n).

A210625 Least semiprime dividing digit reversal of n, or 0 if no such factor.

Original entry on oeis.org

0, 0, 0, 4, 0, 6, 0, 4, 9, 0, 0, 21, 0, 0, 51, 0, 0, 9, 91, 0, 4, 22, 4, 6, 4, 62, 4, 82, 4, 0, 0, 0, 33, 0, 0, 9, 0, 0, 93, 4, 14, 4, 34, 4, 6, 4, 74, 4, 94, 0, 15, 25, 35, 9, 55, 65, 15, 85, 95, 6, 4, 26, 4, 46, 4, 6, 4, 86, 4, 0, 0, 9, 0, 0, 57, 0, 77, 87
Offset: 1

Views

Author

Jonathan Vos Post, Mar 24 2012

Keywords

Comments

Roughly the analog of A209190 (least prime factor of reversal of digits), but with semiprimes (A001358) instead of primes (A000040).

Examples

			a(12) = min {k such that k|R(12) and k = p*q for primes p and q (not necessarily distinct)} = min {k, k|21 and k semiprime} = 21 = 3*7.
a(42) = min {k, k|24 and k semiprime} = min {4,6} = 4 = 2*2.
		

Crossrefs

Programs

  • Maple
    r:= proc(n) option remember; local q;
          `if`(n<10, n, irem(n, 10, 'q') *10^(length(n)-1)+r(q))
        end:
    a:= proc(n) local m, k;
          m:= r(n);
          for k from 4 to m do
             if irem(m, k)=0 and not isprime(k) and
                add(i[2], i=ifactors(k)[2])=2 then return k fi
          od; 0
        end:
    seq(a(n), n=1..100);  # Alois P. Heinz, Mar 26 2012
  • Mathematica
    spd[n_]:=Module[{sps=Select[Divisors[FromDigits[Reverse[ IntegerDigits[n]]]], PrimeOmega[#] == 2&,1]},If[sps=={},0,First[sps]]]; Array[spd,80] (* Harvey P. Dale, Aug 12 2012 *)

Formula

a(n) = A210615(R(n)) = A210615(A004086(n)).
a(p) = 0 iff p in (A004087 union A011557). - Alois P. Heinz, Mar 28 2012

A210665 Least semiprime dividing digit reversal of n-th semiprime, or 0 if no such factor.

Original entry on oeis.org

4, 6, 9, 0, 0, 51, 4, 22, 4, 62, 33, 0, 0, 0, 93, 4, 94, 15, 55, 15, 85, 26, 4, 4, 0, 77, 4, 58, 4, 6, 0, 39, 49, 0, 0, 111, 511, 0, 0, 121, 221, 321, 921, 0, 0, 141, 0, 341, 0, 0, 551, 851, 951, 161, 0, 961, 771, 871, 381, 581, 781, 0, 6, 202, 302, 502, 14
Offset: 1

Views

Author

Jonathan Vos Post, Mar 28 2012

Keywords

Examples

			a(4) = 0 because the 4th semiprime is 10, and R(10) = 1, which is not divisible by any semiprime.
a(6) = 51 because the 6th semiprime is 15, and R(15) = 51, which is itself semiprime.
a(7) = 4 because the 7th semiprime is 21, R(21) = 12, and 4 is the least semiprime divisor of 12.
		

Crossrefs

Programs

  • Maple
    r:= proc(n) option remember; local q;
          `if`(n<10, n, irem(n, 10, 'q') *10^(length(n)-1)+r(q))
        end:
    b:= proc(n) option remember; local k;
          if n=0 then 0
        else for k from b(n-1)+1
               while isprime(k) or 2<>add (i[2], i=ifactors(k)[2])
             do od; k
          fi
        end:
    a:= proc(n) option remember; local m, k;
          m:= r(b(n));
          for k from 4 to m do
             if irem(m, k)=0 and not isprime(k) and
                add(i[2], i=ifactors(k)[2])=2 then return k fi
          od; 0
        end:
    seq(a(n), n=1..100);  # Alois P. Heinz, Mar 28 2012

Formula

a(n) = A210615(A210616(n)).
Showing 1-3 of 3 results.