0, 1, 1, 2, 2, 3, 1, 2, 2, 3, 3, 4, 2, 3, 3, 4, 4, 5, 3, 4, 4, 5, 5, 6, 1, 2, 2, 3, 3, 4, 2, 3, 3, 4, 4, 5, 3, 4, 4, 5, 5, 6, 4, 5, 5, 6, 6, 7, 2, 3, 3, 4, 4, 5, 3, 4, 4, 5, 5, 6, 4, 5, 5, 6, 6, 7, 5, 6, 6, 7, 7, 8, 3, 4, 4, 5, 5, 6, 4, 5, 5, 6, 6, 7, 5, 6, 6, 7, 7, 8, 6, 7, 7, 8, 8, 9, 4, 5, 5, 6, 6, 7, 5, 6, 6, 7
Offset: 0
a(205) = a(1!*1 + 3!*2 + 4!*3 + 5!*1) = 1+2+3+1 = 7. [corrected by Shin-Fu Tsai, Mar 23 2021]
From _Joerg Arndt_, Jun 17 2011: (Start)
n: permutation inv. table a(n) cycles
0: [ 0 1 2 3 ] [ 0 0 0 ] 0 (0) (1) (2) (3)
1: [ 0 1 3 2 ] [ 0 0 1 ] 1 (0) (1) (2, 3)
2: [ 0 2 1 3 ] [ 0 1 0 ] 1 (0) (1, 2) (3)
3: [ 0 2 3 1 ] [ 0 1 1 ] 2 (0) (1, 2, 3)
4: [ 0 3 1 2 ] [ 0 2 0 ] 2 (0) (1, 3, 2)
5: [ 0 3 2 1 ] [ 0 2 1 ] 3 (0) (1, 3) (2)
6: [ 1 0 2 3 ] [ 1 0 0 ] 1 (0, 1) (2) (3)
7: [ 1 0 3 2 ] [ 1 0 1 ] 2 (0, 1) (2, 3)
8: [ 1 2 0 3 ] [ 1 1 0 ] 2 (0, 1, 2) (3)
9: [ 1 2 3 0 ] [ 1 1 1 ] 3 (0, 1, 2, 3)
10: [ 1 3 0 2 ] [ 1 2 0 ] 3 (0, 1, 3, 2)
11: [ 1 3 2 0 ] [ 1 2 1 ] 4 (0, 1, 3) (2)
12: [ 2 0 1 3 ] [ 2 0 0 ] 2 (0, 2, 1) (3)
13: [ 2 0 3 1 ] [ 2 0 1 ] 3 (0, 2, 3, 1)
14: [ 2 1 0 3 ] [ 2 1 0 ] 3 (0, 2) (1) (3)
15: [ 2 1 3 0 ] [ 2 1 1 ] 4 (0, 2, 3) (1)
16: [ 2 3 0 1 ] [ 2 2 0 ] 4 (0, 2) (1, 3)
17: [ 2 3 1 0 ] [ 2 2 1 ] 5 (0, 2, 1, 3)
18: [ 3 0 1 2 ] [ 3 0 0 ] 3 (0, 3, 2, 1)
19: [ 3 0 2 1 ] [ 3 0 1 ] 4 (0, 3, 1) (2)
20: [ 3 1 0 2 ] [ 3 1 0 ] 4 (0, 3, 2) (1)
21: [ 3 1 2 0 ] [ 3 1 1 ] 5 (0, 3) (1) (2)
22: [ 3 2 0 1 ] [ 3 2 0 ] 5 (0, 3, 1, 2)
23: [ 3 2 1 0 ] [ 3 2 1 ] 6 (0, 3) (1, 2)
(End)
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