cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A242522 Number of cyclic arrangements of S={1,2,...,n} such that the difference between any two neighbors is at least 2.

Original entry on oeis.org

0, 0, 0, 0, 1, 5, 33, 245, 2053, 19137, 196705, 2212037, 27029085, 356723177, 5058388153, 76712450925, 1239124984693, 21241164552785, 385159565775633, 7365975246680597, 148182892455224845, 3128251523599365177, 69149857480654157545, 1597343462243140957757
Offset: 1

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Author

Stanislav Sykora, May 27 2014

Keywords

Comments

a(n)=NPC(n;S;P) is the count of all neighbor-property cycles for a specific set S of n elements and a specific pair-property P. For more details, see the link and A242519.
Number of Hamiltonian cycles in the complement of P_n, where P_n is the n-path graph. - Andrew Howroyd, Mar 15 2016
a(n) also agrees with the number of optimal fundamentally distinct radio labelings of the wheel graph on (n+1) nodes for n = 5 up to at least n = 10 (and likely all larger n). - Eric W. Weisstein, Jan 12 2021
a(n) also agrees with the number of optimal fundamentally distinct radio labelings of the n-dipyramidal graph for n = 5 up to at least n = 9 (and likely all larger n). - Eric W. Weisstein, Jan 14 2021

Examples

			The 5 cycles of length n=6 having this property are {1,3,5,2,4,6}, {1,3,5,2,6,4}, {1,3,6,4,2,5}, {1,4,2,5,3,6}, {1,4,2,6,3,5}.
		

Crossrefs

Programs

  • Mathematica
    a[n_ /; n < 5] = 0; a[5] = 1; a[6] = 5; a[n_] := a[n] = n a[n - 1] - (n - 5) a[n - 2] - (n - 4) a[n - 3] + (n - 4) a[n - 4]; Array[a, 24] (* Jean-François Alcover, Oct 07 2017 *)
    Join[{0, 0}, RecurrenceTable[{a[n] == n a[n - 1] - (n - 5) a[n - 2] - (n - 4) a[n - 3] + (n - 4) a[n - 4], a[3] == a[4] == 0, a[5] == 1, a[6] == 5}, a, {n, 20}]] (* Eric W. Weisstein, Apr 12 2018 *)

Formula

a(n) = A002493(n)/(2*n), n>1. - Andrew Woods, Dec 08 2014
a(n) = Sum_{k=1..n} (-1)^(n-k)*k!*A102413(n,k) / (2*n), n>2. - Andrew Woods after Vladeta Jovovic, Dec 08 2014
a(n) = (n-1)!/2 + sum_{i=1..n-1} ((-1)^i * (n-i-1)! * sum_{j=0..i-1} (2^j * C(i-1,j) * C(n-i,j+1))), for n>=5. - Andrew Woods, Jan 08 2015
a(n) = n a(n-1) - (n-5) a(n-2) - (n-4) a(n-3) + (n-4) a(n-4), for n>6. - Jean-François Alcover, Oct 07 2017