cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A268316 a(n) is the number of Dyck paths of length 4n and height n.

Original entry on oeis.org

1, 1, 7, 57, 484, 4199, 36938, 328185, 2937932, 26457508, 239414383, 2175127695, 19827974412, 181266501290, 1661241473220, 15257624681145, 140400178555644, 1294141164447692, 11946771748196428, 110435320379615620, 1022108852175416720, 9470416604629933935
Offset: 0

Views

Author

Gheorghe Coserea, Feb 01 2016

Keywords

Comments

Equivalently, a(n) is the number of rooted plane trees with 2n+1 nodes and height n.

Examples

			For n = 2 the a(2) = 7 solutions are
              /\/\/\       |
LLRLRLRR     /      \     /|\
................................
                /\        /|\
LRLLRRLR     /\/  \/\      |
................................
              /\  /\       /\
LLRRLLRR     /  \/  \     /  \
................................
              /\           /|\
LLRRLRLR     /  \/\/\     /
................................
                  /\      /|\
LRLRLLRR     /\/\/  \        \
................................
              /\/\         /\
LLRLRRLR     /    \/\     /\
................................
                /\/\       /\
LRLLRLRR     /\/    \       /\
		

Crossrefs

Column k=2 of A289481.

Programs

  • Magma
    [Binomial(4*n, n)*2*(2*n+3)*(2*n^2+1)/((3*n+1)*(3*n+2)*(3*n+3)): n in [1..30]]; // Vincenzo Librandi, Feb 04 2016
  • Mathematica
    Table[Binomial[4 n, n] 2 (2 n + 3) (2 n^2 + 1) / ((3 n + 1) (3 n + 2) (3 n + 3)), {n, 1, 25}] (* Vincenzo Librandi, Feb 04 2016 *)
    Drop[CoefficientList[Series[-((-1 + HypergeometricPFQ[{-3/4, -1/2, -1/4}, {1/3, 2/3}, 256 x/27])/(4x)) + 4/5 x HypergeometricPFQ[{5/4, 3/2, 7/4}, {7/3, 8/3}, 256 x/27] + 8/3 x^2 HypergeometricPFQ[{9/4, 5/2, 11/4}, {10/3, 11/3}, 256x/27], {x, 0, 20}], x], 1] (* Benedict W. J. Irwin, Aug 09 2016 *)
  • PARI
    a(n) = binomial(4*n,n) * 2*(2*n+3)*(2*n^2+1)/((3*n+1)*(3*n+2)*(3*n+3));
    vector(21, i, a(i))
    

Formula

a(n) = T(2n,n), where T(n,k) is defined by A080936.
a(n) = binomial(4*n,n) * 2*(2*n+3)*(2*n^2+1)/((3*n+1)*(3*n+2)*(3*n+3)).
a(n) ~ K * A268315^n / sqrt(n), where K = 8/27 * sqrt(2/(3*Pi)) = 0.13649151584...
G.f.: -((3F2(-3/4, -1/2, -1/4; 1/3, 2/3; 256*x/27)-1)/(4*x)) + 4/5*x*3F2(5/4, 3/2, 7/4; 7/3, 8/3; 256*x/27) + 8/3*x^2*3F2(9/4, 5/2, 11/4; 10/3, 11/3; 256*x/27). - Benedict W. J. Irwin, Aug 09 2016
Recurrence: 3*(n+1)*(2*n + 1)*(3*n + 1)*(3*n + 2)*(2*n^2 - 4*n + 3)*a(n) = 8*(2*n - 1)*(2*n + 3)*(4*n - 3)*(4*n - 1)*(2*n^2 + 1)*a(n-1). - Vaclav Kotesovec, Aug 10 2016

Extensions

Added a(0)=1, adjusted b-file - N. J. A. Sloane, Dec 22 2016

A210621 Decimal expansion of 256/81.

Original entry on oeis.org

3, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2, 7, 1, 6, 0, 4, 9, 3, 8, 2
Offset: 1

Views

Author

N. J. A. Sloane, Mar 24 2012

Keywords

Comments

According to Maor (1994), the Rhind Papyrus asserts that a circle has the same area as a square with a side that is 8/9 the diameter of the circle. From this we can determine that 256/81 is one of the ancient Egyptian approximations of Pi. - Alonso del Arte, Jun 12 2012

Examples

			3.1604938271604938271604938271604938271604938271604938271604...
		

References

  • Petr Beckmann, A History of Pi, 3rd Ed., Boulder, Colorado: The Golem Press (1974): p. 12.
  • Calvin C. Clawson, Mathematical Mysteries, The Beauty and Magic of Numbers, Perseus Books, 1996, p. 88.
  • John H. Conway and Richard K. Guy, The Book of Numbers, New York: Springer-Verlag, 1996. See p. 237.
  • Jan Gullberg, Mathematics from the Birth of Numbers, W. W. Norton & Co., NY & London, 1997, ยง3.6 The Quest for Pi, p. 89.
  • Carl Theodore Heisel, Behold! The grand problem no longer unsolved: The circle squared beyond refutation, c. 1935. (proposes Pi = 3 + 13/81)
  • Eli Maor, e: The Story of a Number. Princeton, New Jersey: Princeton University Press (1994): 41, 47 note 1.
  • David Wells, The Penguin Dictionary of Curious and Interesting Numbers. Penguin Books, NY, 1986, Revised edition 1987. See p. 48.

Crossrefs

Programs

Formula

256/81 = (4/3)^4.
Equals 3*A229943 = A255910^2 = A268315/3. - Hugo Pfoertner, Jun 26 2024

Extensions

Offset corrected by Rick L. Shepherd, Jan 06 2014
Showing 1-2 of 2 results.