cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A105800 Greatest Fibonacci number that is a proper divisor of the n-th Fibonacci number; a(1) = a(2) = 1.

Original entry on oeis.org

1, 1, 1, 1, 1, 2, 1, 3, 2, 5, 1, 8, 1, 13, 5, 21, 1, 34, 1, 55, 13, 89, 1, 144, 5, 233, 34, 377, 1, 610, 1, 987, 89, 1597, 13, 2584, 1, 4181, 233, 6765, 1, 10946, 1, 17711, 610, 28657, 1, 46368, 13, 75025, 1597, 121393, 1, 196418, 89, 317811, 4181, 514229, 1, 832040, 1
Offset: 1

Views

Author

Reinhard Zumkeller, Apr 20 2005

Keywords

Comments

a(A001605(n)) = 1.

Crossrefs

Cf. A046022 (gives the positions of ones).

Programs

  • Mathematica
    nn=70;Join[{1,1},With[{fibs=Fibonacci[Range[nn]]},Table[ Max[ Intersection[ Most[Divisors[fibs[[n]]]],fibs]],{n,3,nn}]]] (* Harvey P. Dale, Apr 10 2012 *)

Formula

From Antti Karttunen, Jan 11 2017: (Start)
a(n) = A280686(A000045(n)).
a(n) = A000045(A032742(n)). [Because A000045 is a divisibility sequence.]
a(A032742(n)) = A280688(n).
(End)

A280689 a(n) = A000045(A032742(n)) / A000045(A054576(n)), where A000045(n) gives the n-th Fibonacci number, A032742(n) = the largest proper divisor of n, and A054576(n) = A032742(A032742(n)).

Original entry on oeis.org

1, 1, 1, 1, 1, 2, 1, 3, 2, 5, 1, 4, 1, 13, 5, 7, 1, 17, 1, 11, 13, 89, 1, 18, 5, 233, 17, 29, 1, 122, 1, 47, 89, 1597, 13, 76, 1, 4181, 233, 123, 1, 842, 1, 199, 122, 28657, 1, 322, 13, 15005, 1597, 521, 1, 5777, 89, 843, 4181, 514229, 1, 1364, 1, 1346269, 842, 2207, 233, 39602, 1, 3571, 28657, 709805, 1, 5778, 1, 24157817, 15005, 9349, 89, 271442, 1, 15127, 5777
Offset: 1

Views

Author

Antti Karttunen, Jan 11 2017

Keywords

Comments

A000045 is a divisibility sequence, which guarantees that the result of the division is an integer.

Crossrefs

Programs

Formula

a(n) = A105800(n) / A280688(n) = A105800(n) / A105800(A032742(n)).
a(n) = A000045(A032742(n)) / A000045(A054576(n)).
a(n) = A280690(A032742(n)).

A280687 a(n) = n / A280686(n); n divided by its largest Fibonacci proper divisor, a(1) = 1.

Original entry on oeis.org

1, 2, 3, 2, 5, 2, 7, 4, 3, 2, 11, 4, 13, 7, 3, 2, 17, 6, 19, 4, 7, 11, 23, 3, 5, 2, 9, 14, 29, 6, 31, 4, 11, 17, 7, 12, 37, 19, 3, 5, 41, 2, 43, 22, 9, 23, 47, 6, 49, 10, 17, 4, 53, 18, 11, 7, 19, 29, 59, 12, 61, 31, 3, 8, 5, 22, 67, 2, 23, 14, 71, 9, 73, 37, 15, 38, 77, 6, 79, 10, 27, 41, 83, 4, 17, 43, 29, 11, 89, 18, 7, 46, 31, 47, 19, 12, 97, 49, 33, 20
Offset: 1

Views

Author

Antti Karttunen, Jan 11 2017

Keywords

Comments

For n > 1, a(n) = n divided by the greatest Fibonacci number that divides n and is less than n.

Crossrefs

Programs

Formula

a(n) = n / A280686(n).
a(A000045(n)) = A280690(n).
Showing 1-3 of 3 results.