cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A336405 Decimal expansion of Sum_{n>=1} log(n*sin(1/n)) (negated).

Original entry on oeis.org

2, 8, 0, 5, 5, 6, 3, 3, 6, 2, 2, 9, 1, 5, 5, 0, 7, 9, 6, 0, 2, 0, 3, 9, 6, 8, 0, 9, 3, 9, 1, 9, 8, 3, 6, 2, 1, 7, 4, 5, 0, 2, 8, 2, 9, 4, 5, 9, 7, 1, 5, 1, 5, 5, 9, 0, 4, 7, 7, 3, 8, 5, 3, 7, 9, 5, 1, 5, 6, 7, 7, 2, 1, 0, 9, 9, 9, 1, 1, 6, 9, 0, 7, 4, 2, 7, 7
Offset: 0

Views

Author

Bernard Schott, Jul 20 2020

Keywords

Comments

As v(n) = log(n*sin(1/n)) ~ -1/(6*n^2) when n -> oo, this series is convergent (zeta(2)/6 ~ 0.2741556778...).

Examples

			-0.28055633622915507960203968093919836217450282945971...
		

Crossrefs

Programs

  • Maple
    evalf(sum(log(n*sin(1/n)),n=1..infinity),50);
  • PARI
    sumpos(n=1, log(n*sin(1/n))) \\ Michel Marcus, Jul 20 2020

Formula

Equals Sum_{n>=1} log(n*sin(1/n)).
Equals log(A295219).
From Amiram Eldar, Jul 30 2023: (Start)
Equals Sum_{k>=1} 2^(2*k-1)*(-1)^k*B(2*k)*zeta(2*k)/(k*(2*k)!), where B(k) is the k-th Bernoulli number.
Equals -Sum_{k>=1} zeta(2*k)^2/(k*Pi^(2*k)). (End)

Extensions

More terms from Jinyuan Wang, Jul 21 2020

A363502 Decimal expansion of Product_{k>=1} k*sinh(1/k).

Original entry on oeis.org

1, 3, 0, 7, 9, 7, 0, 9, 3, 6, 6, 6, 4, 2, 8, 3, 6, 4, 9, 0, 1, 2, 1, 0, 4, 4, 7, 6, 0, 0, 7, 0, 5, 6, 3, 2, 0, 4, 6, 5, 5, 1, 5, 6, 8, 3, 1, 3, 8, 2, 2, 3, 5, 0, 6, 7, 0, 5, 6, 4, 8, 2, 2, 5, 9, 7, 9, 2, 2, 9, 3, 0, 9, 8, 0, 0, 9, 9, 5, 4, 3, 6, 4, 3, 2, 1, 9, 2, 2, 8, 4, 8, 3, 5, 9, 9, 9, 0, 4, 7, 0, 1, 3, 7, 6
Offset: 1

Views

Author

Amiram Eldar, Jul 30 2023

Keywords

Examples

			1.30797093666428364901210447600705632046551568313822...
		

Crossrefs

Similar constants: A118817, A249673, A295219.

Programs

  • Maple
    evalf(exp(sum(log(k*sinh(1/k)), k = 1 .. infinity)), 120)
  • Mathematica
    Block[{$MaxExtraPrecision = 1000}, RealDigits[Exp[Sum[(-1)^(k + 1) * Zeta[2*k]^2 / (k*Pi^(2*k)), {k, 1, 200}]], 10, 120][[1]]]
  • PARI
    exp(-sumpos(k=1,-log(k*sinh(1/k))))

Formula

Equals exp(Sum_{k>=1} 2^(2*k-1)*B(2*k)*zeta(2*k)/(k*(2*k)!)), where B(k) is the k-th Bernoulli number.
Equals exp(Sum_{k>=1} (-1)^(k+1)*zeta(2*k)^2/(k*Pi^(2*k))).
Showing 1-2 of 2 results.